Answer:
Four unique planes
Step-by-step explanation:
Given that the points are non co-planar, triangular planes can be formed by the joining of three points
The points will therefore appear to be at the corners of a triangular pyramid or tetrahedron such that together the four points will form a three dimensional figure bounded by triangular planes
The number of triangular planes that can therefore be formed is given by the combination of four objects taking three at a time as follows;
₄C₃ = 4!/(3!×(4-3)! = 4
Which gives four possible unique planes.
Answer:
3.75
Step-by-step explanation:
3/4 times 5 =3 3/4
Answer:
H and b
Step-by-step explanation:
Answer:
<h2>
sin(01) = -32.70/13</h2>
Step-by-step explanation:
Given cos(01) = -30/13 where angle 01 is located in quadrant III. In the third quadrant, both cos and sin are negative. only tan is positive.
To calculate sin(01), we will apply the trigonometry expression as shown below;
cos(01) = -30/13
According to SOH CAH TOA;
cos(01) = adjacent/hypotenuse = -30/13
sin(01) = opposite/ hypotenuse
To get the hypotenuse, we will use the pythagoras theorem
![hyp^{2}=opp^{2}+adj^{2} \\opp^{2}= hyp^{2}-adj^{2}\\opp^{2}= 13^{2} -(-30^{2} )\\opp^{2} = 169+900\\opp^{2}=1069\\opp = \sqrt{1069} \\opp = 32.70\\](https://tex.z-dn.net/?f=hyp%5E%7B2%7D%3Dopp%5E%7B2%7D%2Badj%5E%7B2%7D%20%20%20%5C%5Copp%5E%7B2%7D%3D%20%20hyp%5E%7B2%7D-adj%5E%7B2%7D%5C%5Copp%5E%7B2%7D%3D%2013%5E%7B2%7D%20-%28-30%5E%7B2%7D%20%29%5C%5Copp%5E%7B2%7D%20%3D%20169%2B900%5C%5Copp%5E%7B2%7D%3D1069%5C%5Copp%20%3D%20%5Csqrt%7B1069%7D%20%5C%5Copp%20%3D%2032.70%5C%5C)
sin(01) = 32.70/13
Since sin is also negaitve in the third quadrant, the value of
sin(01) = -32.70/13
![01 = cos^{-1}- 30/13](https://tex.z-dn.net/?f=01%20%3D%20cos%5E%7B-1%7D-%2030%2F13)
Answer:
b = 5
Step-by-step explanation:
if parallelogram is a rectangle, then the two diagonals has the same length
10/12 x(24/5 x b - 36/5) = 2/3 x (3b + 6)
4b - 6 = 2b + 4
2b = 10
b = 5