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Naddika [18.5K]
3 years ago
14

Please help me in this question, pleaee

Mathematics
1 answer:
-Dominant- [34]3 years ago
7 0

Answer:

They will meet in 5:30.

Step-by-step explanation:

'Cause you have to fin the LCM (least common multiple). And in this case the LCM is 30.

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Given the formula 1 = prt, which shows an equation solving for r?
lesya [120]

Answer:

r = 1/pt.

Step-by-step explanation:

1 = prt

Divide both sides of the formula by pt:

`1 / pt = r.

3 0
2 years ago
Evaluate the expression.<br> 38 +16 - 12 - 2 - (302)<br> Enter your answer in the box.
masha68 [24]

Answer:

-262

Step-by-step explanation:

Evaluate Subtraction & Addition from right to left [or left to right, as long as you know what you are doing]:

38 + 16 - 12 - 2 - 302

|_______||____________|

44 - 316 =  -262

I am joyous to assist you anytime.

5 0
3 years ago
solve the equations below. make sure you say how many solutions each equation has(MCC.8.EE.7a) A. 5p-9=7p-19 b. 5p-9= 5p-19 C. 5
Sedaia [141]
<h3>Answer:</h3>
  • A) p = 5, one solution
  • B) no solutions
  • C) infinite solutions
<h3>Step-by-step explanation:</h3>

A) Add 19-5p to each side of the equation:

... 10 = 2p

... 5 = p . . . . . divide by the coefficient of p

B) Subtract 5p from both sides of the equation:

... -9 = -19 . . . . . there is <em>no value of p</em> that will make this true. (No solution.)

C) Subtract 5p from both sides of the equation:

... -9 = -9 . . . . . this is true for <em>every value of p</em>. (Infinite solutions.)

6 0
2 years ago
Given: △ABC; AB=BC, m∠BDA = 60°, BD=4 cm, BD ⊥ BA . Find: DC, AC.
vekshin1

Answer:

DC = 10.93 cm ,  AC = 9.8 cm

Step-by-step explanation:

From trigonometry;

⇒ Tan 60 = AB/BD

⇒AB = BD Tan 60 ( where BD = 4 cm )

⇒ AB = 6.93 cm

Also, AB=BC , therefore;

⇒ BC = 6.93 cm

⇒ Cos 60 = BD/AD

⇒ AD = BD/ Cos 60 = 4/Cos 60

⇒ AD = 8 cm

From Pythagoras theorem;

⇒ AC^{2} = AB^{2} + BC^{2} = (6.93)^{2} + (6.93)^{2}

⇒ AC = \sqrt{96.05} = 9.80 cm

⇒ DC = BD + BC = 4 + 6.93

⇒ DC = 10.93 cm

8 0
3 years ago
Use​ Gauss's approach to find the following sums​ (do not use​ formulas). 1+3+5+7+...999
muminat
S=1+3+5+\cdots+995+997+999
S=999+997+995+\cdots+5+3+1
\implies 2S=(1+999)+(3+997)+(5+995)+\cdots+(995+5)+(997+3)+(999+1)

2S=\underbrace{1000+1000+\cdots+1000+1000}_{500\text{ times}}

(We are adding 500 instances of 1000 because that's how many odd numbers there are between 1 and 1000, inclusive.)

2S=500\times1000=500000
\implies S=250000
4 0
3 years ago
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