Question

Write an equation of the line passing through point P(2, 3) that is perpendicular to the line y-4=-2(x+3) .

Answer 1

$\\ \sf\longmapsto y-4=-2(x+3)$

Here slope is -2

• The perpendicular line have additive and multiplicative inverse slope

m=1/2

Put co-ordinates of P in equation

$\\ \sf\longmapsto y-3=\dfrac{1}{2}(x+2)$

Answer 2

Answer:

• y - 3 = 1/2(x - 2)

Step-by-step explanation:

The given line has a slope of -2.

The perpendicular line will have a negative-reciprocal slope:

• m = 1/2

Use same point-slope form and the point P(2, 3):

• y - y₁ = m(x - x₁)
• y - 3 = 1/2(x - 2)