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3 years ago

I need the Volume and Surface Area I need now please

Mathematics

1 answer:

Vesnalui [34]3 years ago

8 0

Step-by-step explanation:

Volume = 1/3 pi r h

Sa = pi r l

L = root of r2 + h2

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Give the values of a, b, and c needed to write the equation's general form. 2/3(x - 4)(x + 5) = 1

ale4655 [162]

The first step is to write this equation into general form. The general form of an equation is:

ax^2 + bx + c = 0

To make this equation to general form, you have to simplify the equation first.

2/3(x-4) (x+5) = 1

2/3 (x^2 + 5x – 4x – 20) = 1

2/3(x^2 + x -20) = 1

2/3x^2 + 2/3x – 40/3 = 1

2/3x^2 + 2/3x – 40/3 – 1 = 0

2/3x^2 +2/3x – 43/3 = 0

Therefore, a = 2/3 ; b = 2/3 ; c = -43/3

4 0

3 years ago

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How many line of symmetry does a hexagon has?

yaroslaw [1]

Since it is a hexagon and it has 6 sides (and we assume it is regular since it doesn't tell us otherwise) then the hexagon will have 6 lines of symmetry (:

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3 years ago

What is 5z^3+5z^2-6z-6

DochEvi [55]

Answer: (z + 1) (5z2 -6)

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3 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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2 years ago

The work of a student to solve a set of equations is shown below: Equation 1: x + 2y = 10 Equation 2: 2x + 5y = 15 Step 1: −2(x

DIA [1.3K]

−2x − 4y = −10 2x + 5y = 15

6 0

3 years ago

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