Given:
t A = 2.4 h
t B = 4 h
v A = 22 + v B
Solution:
Distance A and distance B is the same, distance could be defined using formula d = v × t
d A = d B
(v A × t A) = (v B × t B)
plug in the numbers
v A × 2.4 = v B × 4
(22 + vB) × 2.4 = 4 vB
remove the parenthesis using distributive property
(22 × 2.4) + (2.4 × vB) = 4vB
52.8 + 2.4vB = 4vB
add like terms
52.8 = 4vB - 2.4vB
52.8 = 1.6vB
52.8/1.6 = vB
vB = 33
the speed of car B is 33 mph
vA = 22 + vB
vA = 22 + 33
vA = 55
the speed of car A is 55 mph
5x+2y=7
7x-2y=5 its subtract not add
B(cone)=B(pyramid)=r²π
V(pyramid)=1/3 * B * H = 1/3 * r² π * 3 r ( 3 will cancel out )= r³ π
Answer: r³ π
Perimeter = a + b + c = 30
Area = 1/2 x a x b = 30
Multiples of 30: 2, 3, 5, 6, 10, 12, 15
For perimeter c = 30- (a+b)
C= sqrt( a^2 + b^2)
Using the possible combinations of the above:
5 and 12:
C = sqrt(5^2 + 12^2) = 13
5 + 12 + 13 = 30 for the perimeter
Area = 1/2 x 5 x 12 = 30
The sides are 5, 12 and 13 cm
V= LWH so 3.75cm^3 or 3 (3/4)
Multiply those three sides and it comes out to 3.75