Shaded part means the yellow part
- The two sets are S and Y.
- The centre intersection part is A
- All the areas occupied by both sets is AUB .
Rest part :-
I have nooo clue the problem doesn’t make sense
This question is easy once you understand. So when adding, subtracting, multiplying, or dividing with whole numbers you turn it into a fraction. So 12 is going to become 12/1. 8 1/8 is a mixed number so we have to turn it into an incomplete fraction. Here is how you do it. Multiply the denominator by the who number. So 8 x 8 = 64. Then you add your product to the numerator, which will make it 65. Then after this you keep your denominator giving you 65/8. Now we have to find the common denominator by finding the LCM. So the LCM is 8. Next we divide the old denominator by the new denominator. So 1 goes into 8, 8 times. And next 8 x the numerator. so 8 x 12 = 96. We do the same to the other side. Now we have 96/8 - 65/8 = 31/8. Finally we make this a mixed number. So 31 divided by 8. So you should get 3 7/8.
I hope this helps! :)
Answer: 1
f(x) = 3x - 4 => f(3) = 3.3 - 4 = 9 - 4 = 5
g(x) = x² => g(2) = 2² = 4
=> f(3) - g(2) = 5 - 4 = 1
Step-by-step explanation:
Answer:
3 values
Step-by-step explanation:
2x +8 <22 and 3x >9
Solve the two inequalities separately and then put them back together
2x +8 <22
Subtract 8 from each side
2x +8-8 <22 -8
2x < 14
Divide by 2
2x/2 < 14/2
x < 7
Then solve the second inequality
3x>9
Divide by 3
3x/3>9/3
x >3
Putting them back together
x>3 and x < 7
Since it has to be an integer
4,5,6 are possible choices
3 values
