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evablogger [386]

2 years ago

11

What is the slope of a line whose graph is parallel to the graph of -3x+y=2?

1 answer:

liq [111]2 years ago

7 0

Answer:

Step-by-step explanation:

if the lines are parallel they have the same gradient.

rearrange the equation to make y the subject and then use the m value as gradient.

-3x=2-y

-3x-2=-y

y=-(-3x-2)

y=3x+2

therefore m=3

slope is 3

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What is the GCF of and 55 and 80 *

Zarrin [17]

The Greatest Common Factor of 55 and 80 is 5.

3 0

3 years ago

Please help me with parts A, B, and C.

leonid [27]

Answer:

(a) scalene, see attachment

(b) acute, see attachment

(c) correct; isosceles

Step-by-step explanation:

(a) The sides of the triangle all have different lengths, so the triangle is scalene. Differences in coordinates between the points of the triangle are (6, 2), (5, 2), and (4, 1), so no two distances between these points can be the same.

__

(b) The angle opposite the longest side is clearly an acute angle, so the triangle is an acute triangle.

__

(c) Miles and Brad live on the same north/south line. Jose lives at a distance that is halfway between those houses in the north-south direction. Hence the distance to Miles' and Brad's houses must be the same from Jose's house. That means the triangle connecting Miles', Brad's, and Jose's houses will be an isosceles triangle.

4 0

3 years ago

Ms Lucas has 9 cases of crayon with 52 boxes in each case Ms Bruns has 6 cases of crayon with a 104 in each case How many boxes

saveliy_v [14]

Answer:

1092

Step-by-step explanation:

Step one:

given data

Ms Lucas has 9 cases of crayon with 52 boxes in each case

total crayon is

9*52= 468

Ms Bruns has 6 cases of crayon with a 104 in each case

total crayon is

6*104= 624

The total crayon is

468+624= 1092

5 0

3 years ago

You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

3 years ago

Compute the probability of the event E1 that Bob wins in a duel against Eve alone, assuming he shoots first. (Hint: Let x be the

skad [1K]

Answer: Hello your question is incomplete attached below is the missing

n ( 1 + n )

Step-by-step explanation:

P( Bob hits target ) = 1/3

P( Eve hits target ) = 2/3

P( Carol hits target ) = 1

<u>Compute the P that Bob wins in a duel against Eve alone</u>

P(Bob hits the target in first shot ) = n = 1/3

P(Bob hits the target in second shot ) = n^2 = ( 1/3 * 1/3 ) = 1/9

hence the probability of Bob winning( i.e. P( Bob wins Event E1 ) = n + n^2 = n ( 1 + n )

6 0

3 years ago