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NARA [144]
3 years ago
10

Bvtcctctctc CJ bububuv

Mathematics
1 answer:
Brut [27]3 years ago
5 0

Answer:

A) y+7=-3(x-4)

Step-by-step explanation:

Hi there!

The given equations are written in point-slope form: y-y_1=m(x-x_1) where <em>m</em> is the slope of the line and (x_1,y_1) is a point that falls on the line

Notice how the line is travelling infinitely down as x increases. This means that the slope is negative.

Therefore, the equation of the line is either A or B.

Now, let's look at A:

y+7=-3(x-4)

This equation suggests that the point (4,-7) falls on the line, which it does.

Therefore, the equation of the graph is y+7=-3(x-4).

I hope this helps!

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Find the fifth roots of 32(cos 280° + i sin 280°)
shusha [124]

Answer:

The fifth root is 2[cos(56°) + i sin(56°)]

Step-by-step explanation:

* To solve this problem we must revise De Moiver's rule

- In the complex number with polar form

∵ z = r(cosФ + i sinФ)

∴ z^n = r^n(cos(nФ) + i sin(nФ))

* In the problem

- The fifth root means z^(1/5)

- We can put 32 as a form a^n

∵ 32 = 2 × 2 × 2 × 2 × 2 = 2^5

∴ z = 2^5[cos(280°) + i sin(280°)]

* Lets find z^(1/5)

*z^{\frac{1}{5}}=[2^{5}]^{\frac{1}{5} } (cos(\frac{1}{5})(280)+isin(\frac{1}{5})(280)

*(2^{5})^{\frac{1}{5}}=2^{5.\frac{1}{5}}=2

∴ z^(1/5) = 2[cos(56) + i sin(56)]

* The fifth root of 32[cos(280°) + i sin(280°)] is 2[cos(56°) + i sin(56°)]

 

4 0
3 years ago
Can you plz help me solve these plss i begg
Akimi4 [234]

Answer:

a): A line has a total degree of 180. So just subtract it. 180-92 is

y=88

b): Similar to the previous, a right angle has a total angle of 90. 90-45=45.

y=45.

These are all the ones I can figure out. I hope someone else can get c) and d).

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3 years ago
Which of the following is a correct interpretation of the expression 2 +7
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Nine.....................
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