Marilyn's finance charge at the end of the first month will be
$991.38 × 0.199/12 = $16.44
The balance subject to the next month's finance charge will be
$991.38 +16.44 -410.00 = $597.82
The finance charge at the end of the second month will be
$597.82 × 0.199/12 = $9.91
The balance remaining after the second payment will be
$597.82 +9.91 -410.00 = $197.73
The finance charge applied at the end of the third month is
$197.73 × .199/12 = $3.28
so Marilyn can make one final payment of
$197.73 +3.28 = $201.01
to pay off the balance.
In all, Marilyn has paid 2×$410.00 +201.01 =
$1021.01 . . . . . . . . corresponds to the first choice_____
In real life, Marilyn's credit card may not accrue any finance charge until after the first statement on which the charge appears. Thus the total cost of the purchase may be only $1004.02. The attached spreadsheet shows the beginning balance and the finance charges for each month for the two different scenarios.
Answer:
A
Step-by-step explanation:
Both equal 15,625
Using the linear equation, T = 20x + 31, the total number of computers at the end of 2005 is: C. 191.
<h3>How to Use a Linear Equation?</h3>
A linear equation is expressed as y = mx + b, where x is a function of y, m is the rate of change and b is the y-intercept or starting value.
In the scenario stated, we are given the linear equation for total number of laptop computers at the school after 1997 as, T = 20x + 31.
Rate of change = 20
y-intercept/starting value = 31
x = 2005 - 1997 = 8
To find the total number of laptop computers at Grove High School at the end of 2005 (T), substitute x = 8 into the equation, T = 20x + 31.
T = 20(8) + 31
T = 160 + 31
T = 191 computers.
Thus, total number of computers at the end of 2005 is: C. 191.
Learn more about linear equation on:
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Answer:
This is what I put:
Step-by-step explanation: