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satela [25.4K]
2 years ago
10

398•0=0 name the property

Mathematics
1 answer:
anastassius [24]2 years ago
4 0
The zero property of multiplication
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What is the value of x if HF = 4x+1 and AB = 12x-3?|<br><br><br> Given m
Reptile [31]

Answer: <em>x = 1.25</em>

Step-by-step explanation:

<em>HF - is the middle line of the triangle ABC.</em>

HF=\dfrac{1}{2} AB\\\\HF=4x+1\\AB=12x-3\\\\4x+1=\dfrac{1}{2}  \cdot (12x-3)\\\\4x+1=\dfrac{12x-3}{2} \\\\(4x+1) \cdot 2 =12x-3\\8x+2=12x-3\\8x+2-12x=12x-3-12x\\-4x+2=-3\\-4x+2-2=-3-2\\-4x=-5\\-4x \cdot (-1)=-5 \cdot (-1)\\4x=5\\4x \div 4=5 \div 4\\x=1.25

7 0
2 years ago
How far is Mars from the sun actually formatted
pav-90 [236]

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228 kilometers away

Step-by-step explanation:

6 0
3 years ago
FInd the slope of these graphs plz :(
Lerok [7]

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2. Slpe=20

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7 0
2 years ago
the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?
miss Akunina [59]
The equation of a circle in standard form is

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the center of the circle, and r is the radius if the circle.

We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.

M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).

To find the radius, we find the length of the given diameter and divided by 2.

d = \sqrt{(-6 - 6)^2 + (6 - (-2))^2)}

d = \sqrt{144 + 64}

d = \sqrt{208}

r = \dfrac{d}{2} = \dfrac{\sqrt{208}}{2} = \dfrac{\sqrt{208}}{\sqrt{4}} = \sqrt{52}

(x - 0)^2 + (y - 2)^2 = (\sqrt{52})^2

x^2 + (y - 2)^2 = 52
7 0
3 years ago
I need help with this problem ​
vazorg [7]
C,d hope it helped





I wrote this because 20 word rule
4 0
3 years ago
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