Answer: Last option.
Step-by-step explanation:
For this exercise you need to find the Discriminant.
The formula used to find the Discriminant, is the following:
In this case, given the Quadratic equation:
You can identify that:
Knowing those values, you must substitute them into the formula and then you must evaluate in order to find the Discriminant.
You get that this is:
By definition, if:
Then the Quadraitc equation has 2 nonreal solutions.
Answer:
<u>∠IJG = 123° </u>
Step-by-step explanation:
Since AB║CD, EF ║GH, we can use the Corresponding Angles Postulate, for finding the following congruent angles:
∠IKL ≅ ∠EIJ and ∠EIJ ≅ ∠GJA
∠GJA and ∠IJG are supplementary, therefore:
∠GJA + ∠IJG = 180°
∠IJG = 180° - 57°
<u>∠IJG = 123°</u>
The domain and range of g are "all real numbers," so you want to find the range of f when its argument is from the set "all real numbers." That range is y > 0. The appropriate choice is
D. domain: all real numbers; range: y > 0
I'll solve for y
xy+(4(20))>x-5y(2+9-7)
xy+4(20)>x-5y(2+9-7)
xy+4(20)>x-5y(4)
xy+4(20)>x-20y
xy+80>x-20y
xy+20y+80>x
y(x+20)>-80+x
y>(-80+x)/(x+20)
