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horrorfan [7]
3 years ago
15

Ammonia gas has a molar mass of approximately 17 grams per mole. At 290k and 1.2 atm, a sample of ammonia has a volume of 3.7 L.

In three to five sentences, explain how you can find the mass of the ammonia. Then, given R= 0.0821L.atm/mol.k, calculate the mass.
Chemistry
2 answers:
yanalaym [24]3 years ago
8 0

Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L. You can calculate the mass of ammonia by using the given equation to get the answer of, 0.00007393.

This is the answer I used so make sure you alter it slightly to not get caught

dlinn [17]3 years ago
3 0

We have that for the Question, it can be said that the mass of Ammonia is

Mass_a=3.162grams

From the question we are told

<em>Ammonia </em>gas has a <u>molar</u> mass of approximately 17 <u>grams </u>per mole. At 290k and 1.2 atm, a sample of <em>ammonia </em>has a volume of 3.7 L. In <em>three </em>to five sentences, explain how you can find the mass of the <em>ammonia</em>. Then, given R= 0.0821L.atm/mol.k, calculate the mass.

Generally the equation for the   is mathematically given as

PV=nRT\\\\n=\frac{PV}{RT}\\\\n=0.186 moles\\\\

Now the mass of ammonia is

Mass_a=0.186*17\\\\Mass_a=3.162grams

Hence the mass of Ammonia is

Mass_a=3.162grams

For more information on this visit

brainly.com/question/23379286

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A student ran the following reaction in the laboratory at 311 K:CH4(g) + CCl4(g) 2CH2Cl2(g)When she introduced 4.10×10-2 moles o
statuscvo [17]

<u>Answer:</u> The value of K_{eq} is 0.044

<u>Explanation:</u>

We are given:

Initial moles of methane = 4.10\times 10^{-2}mol=0.0410moles

Initial moles of carbon tetrachloride = 6.51\times 10^{-2}mol=0.0651moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}

So, concentration of methane = \frac{0.0410}{1.00}=0.0410M

Concentration of carbon tetrachloride = \frac{0.0651}{1.00}=0.0651M

The given chemical equation follows:

                    CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)

<u>Initial:</u>          0.0410    0.0651

<u>At eqllm:</u>     0.0410-x   0.0651-x       2x

We are given:

Equilibrium concentration of carbon tetrachloride = 6.02\times 10^{-2}M=0.0602M

Evaluating the value of 'x', we get:

\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M

Now, equilibrium concentration of methane = 0.0410-x=[0.0410-0.0049]=0.0361M

Equilibrium concentration of CH_2Cl_2=2x=[2\times 0.0049]=0.0098M

The expression of K_{eq} for the above reaction follows:

K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}

Putting values in above expression, we get:

K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044

Hence, the value of K_{eq} is 0.044

8 0
3 years ago
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7 0
4 years ago
in which compound does iodine have an oxidation number of 3? question 12 options: a) hio2 b) hi c) hio4 d) hio e) hio3
andrew-mc [135]

The oxidation state of an element is an indicator of the total number of electrons that have been removed from the atom. The oxidation state of a)HIO₂ is +3, meaning that three electrons have been removed from the atom.

The oxidation state of an atom is determined by the oxidation number of its constituent elements. In the case of HIO₂, the oxidation number of each atom is determined by the sum of the number of valence electrons and the charge of the ion. The oxidation number of hydrogen is +1, the oxidation number of oxygen is -2 and the oxidation number of iodine is +7. When these values are added together, the oxidation number of HIO₂ is +3.

Oxidation states can be useful in predicting the stability of a compound and the reactivity of the atoms within it. In this case, the oxidation state of HIO₂ indicates that it is relatively stable, as the total oxidation number for the molecule is positive. The positive oxidation state also indicates that HIO₂ is likely to be fairly unreactive, as the electrons in the molecule are already well-bonded and not likely to be easily transferred.

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5 0
2 years ago
Using the activity series provided. Which reactants will form products?
Butoxors [25]
The series of metals shown above is what we call the activity series. This is a guide for us to know what products are formed during a metal displacement reaction. A metal must be above the other metallic compound for displacement to occur. 

1. Ag is way below the series compared to Na. No reaction occurs.
2. Al  is above Fe, no reaction occurs. 
3. Na is above Ni, no reaction will occur. 
4. Fe is a more active metal than copper. A displacement reaction will occur. 


5 0
3 years ago
Read 2 more answers
Consider the reaction of magnesium metal with hydrochloric acid to produce magnesium chloride and hydrogen gas. If 3.29 mol of m
gregori [183]

Answer:

1.645 moles of excess reactant that is of magnesium metal are left over.

Explanation:

Moles of magnesium metal = 3.29 mol

Moles of HCl = 3.29 mol

Mg(s)+2HCl(aq)\rightarrow MgCl_2(aq)+H_2(g)

According to recation, 2 moles of HCl reacts with 1 mol of magnesium metal, then 3.29 moles of HCl will react with :

\frac{1}{2}\times 3.29 mol=1.645 mol of magnesium metal

Moles of HCl left = 3.29mol - 3.29 mol = 0

Moles of magnesium metal left = 3.29 mol - 1.645 mol = 1.645 mol

1.645 moles of excess reactant that is of magnesium metal are left over.

7 0
3 years ago
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