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horrorfan [7]
2 years ago
15

Ammonia gas has a molar mass of approximately 17 grams per mole. At 290k and 1.2 atm, a sample of ammonia has a volume of 3.7 L.

In three to five sentences, explain how you can find the mass of the ammonia. Then, given R= 0.0821L.atm/mol.k, calculate the mass.
Chemistry
2 answers:
yanalaym [24]2 years ago
8 0

Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L. You can calculate the mass of ammonia by using the given equation to get the answer of, 0.00007393.

This is the answer I used so make sure you alter it slightly to not get caught

dlinn [17]2 years ago
3 0

We have that for the Question, it can be said that the mass of Ammonia is

Mass_a=3.162grams

From the question we are told

<em>Ammonia </em>gas has a <u>molar</u> mass of approximately 17 <u>grams </u>per mole. At 290k and 1.2 atm, a sample of <em>ammonia </em>has a volume of 3.7 L. In <em>three </em>to five sentences, explain how you can find the mass of the <em>ammonia</em>. Then, given R= 0.0821L.atm/mol.k, calculate the mass.

Generally the equation for the   is mathematically given as

PV=nRT\\\\n=\frac{PV}{RT}\\\\n=0.186 moles\\\\

Now the mass of ammonia is

Mass_a=0.186*17\\\\Mass_a=3.162grams

Hence the mass of Ammonia is

Mass_a=3.162grams

For more information on this visit

brainly.com/question/23379286

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oee [108]

Answer: The IUPAC name of CH_3C\equiv CCH_2CH_2Cl is 5-chloro-2-pentyne

Explanation:

1. First select the longest possible carbon chain.  For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

2. The longest possible carbon chain should contain all the bonds and functional groups.

3. The numbering is done in such a way that the carbon containing the functional group or substituent gets the lowest number. Triple bond is given priority over substituent halogen.

4. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne.

Thus the IUPAC name of CH_3C\equiv CCH_2CH_2Cl is 5-chloro-2-pentyne

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3 years ago
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5 0
4 years ago
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inessss [21]

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\\ \sf\longmapsto 50ml-30ml=20ml

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3 0
3 years ago
40.0% C, 6.72% H, 53.29%, O. Molar mass is 60 g/mol. Determine the empirical and molecular formula.
arsen [322]

Answer:

Molecular formula: C₂H₄O₂

Empirical formula: CH₂O

Explanation:

40 % C, 6.72 % H and 53.29 % O states the centesimal composition of the compound. These data means that in 100 g of compound we have x grams of a determined element.

We divide the mass by the molar mass of each:

40 g / 12 g/mol = 3.33 moles of C

6.72 g / 1 g/mol = 6.72 moles of H

53.29 g / 16 g/mol = 3.33 moles of O

We can determine rules of three to get, the molecular formula.

In 100 g of compound we have 3.33 moles of C, 6.72 moles of H and 3.33 moles of O; therefore in 60 g (1 mol) we must have

- (60 . 3.33) / 100 = 2 moles of C

- (60 . 6.72) / 100 = 4 moles of H

- (60 . 3.33) / 100 = 2 moles of O

Molecular formula is C₂H₄O₂

Empirical formula has the lowest suscripts; we divide by two, so the empirical formula is CH₂O

3 0
3 years ago
BrO3- (aq) + NO2(aq) → Br-(aq) + NO3-(aq) Balance this reaction in acidic conditions?
Thepotemich [5.8K]

Answer:

BrO₃⁻ (aq) + NO₂(aq) + 4 H⁺→ Br⁻(aq) + NO₃⁻ + 2 H₂O

Explanation:

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.  

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Then, taking into account all of the above, you can determine the amount of elements on each side of the equation:

Left side: 1 Br, 5 O and 1 N

Right side: 1 Br, 3 O and 1 N

If the reaction occurs in an acidic medium:

  • Each excess oxygen atom is balanced by adding a molecule of water to the other side of the reaction.
  • Hydrogens are balanced by adding protons (H⁺) on the opposite side to the water molecules.

So, balancing the oxygen:

BrO₃⁻ (aq) + NO₂(aq) → Br⁻(aq) + NO₃⁻ + 2 H₂O

Left side: 1 Br, 5 O and 1 N

Right side: 1 Br, 5 O, 1 N and 4 H

Then, balancing the hydrogens:

<em><u>BrO₃⁻ (aq) + NO₂(aq) + 4 H⁺→ Br⁻(aq) + NO₃⁻ + 2 H₂O</u></em>

Left side: 1 Br, 5 O, 1 N and 4 H

Right side: 1 Br, 5 O, 1 N and 4 H

You can see that you have the same amount on each side of the reaction. So the reaction is balanced.

6 0
3 years ago
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