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NeX [460]
3 years ago
10

Consider the reaction of magnesium metal with hydrochloric acid to produce magnesium chloride and hydrogen gas. If 3.29 mol of m

agnesium and 3.29 mol of hydrochloric acid are reacted, how many moles of excess reactant are left over?
a. 6.58 mol
b. 3.29 mol
c. 2.47 mol
d. 40.0 mol
Chemistry
1 answer:
gregori [183]3 years ago
7 0

Answer:

1.645 moles of excess reactant that is of magnesium metal are left over.

Explanation:

Moles of magnesium metal = 3.29 mol

Moles of HCl = 3.29 mol

Mg(s)+2HCl(aq)\rightarrow MgCl_2(aq)+H_2(g)

According to recation, 2 moles of HCl reacts with 1 mol of magnesium metal, then 3.29 moles of HCl will react with :

\frac{1}{2}\times 3.29 mol=1.645 mol of magnesium metal

Moles of HCl left = 3.29mol - 3.29 mol = 0

Moles of magnesium metal left = 3.29 mol - 1.645 mol = 1.645 mol

1.645 moles of excess reactant that is of magnesium metal are left over.

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Answer : The value of equilibrium constant for this reaction at 328.0 K is 1.70\times 10^{15}

Explanation :

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy  = ?

\Delta H^o = standard enthalpy = 151.2 kJ = 151200 J

\Delta S^o = standard entropy = 169.4 J/K

T = temperature of reaction = 328.0 K

Now put all the given values in the above formula, we get:

\Delta G^o=(151200J)-(328.0K\times 169.4J/K)

\Delta G^o=95636.8J=95.6kJ

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln k

where,

\Delta G^o = standard Gibbs free energy  = 95636.8 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 328.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

95636.8J=-(8.314J/K.mol)\times (328.0K)\times \ln k

k=1.70\times 10^{15}

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Determine the a) energy (in eV) and b) wavelength (in cm) corresponding to blue light of frequency 670 THz
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Answer :

(a) The energy of blue light (in eV) is 2.77 eV

(b) The wavelength of blue light is 4\times 10^{-5}cm

Explanation:

The relation between the energy and frequency is:  

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where,

h = Plank's constant = 6.626\times 10^{-34}J.s

Given :

Frequency = 670THz=670\times 10^{12}s^{-1}

Conversion used :

1THz=10^{12}Hz\\1Hz=1s^{-1}\\1THz=10^{12}s^{-1}

So,  

Energy=(6.626\times 10^{-34}J.s)\times (670\times 10^{12}s^{-1})

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Also,  

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So,  

Energy=(4.44\times 10^{-19})\times (6.24\times 10^{18}eV)

Energy=2.77eV

The energy of blue light (in eV) is 2.77 eV

The relation between frequency and wavelength is shown below as:

Frequency=\frac{c}{Wavelength}

Where,

c = the speed of light = 3\times 10^8m/s

Frequency = 670\times 10^{12}s^{-1}

So, Wavelength is:

670\times 10^{12}s^{-1}=\frac{3\times 10^8m/s}{Wavelength}

Wavelength=\frac{3\times 10^8m/s}{670\times 10^{12}s^{-1}}=4\times 10^{-7}m=4\times 10^{-5}cm

Conversion used : 1m=100cm

The wavelength of blue light is 4\times 10^{-5}cm

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