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2 years ago

A snail can crawl at a rate of 6 cm in 0.75 minutes. Which representation shows the distance a snail can travel at this rate?

Mathematics

1 answer:

Bogdan [553]2 years ago

7 0

Answer: 0.00133m/s

Step-by-step explanation:

Given

distance crawled by the snail = 6cm = 0.06m

Time taken = 0.75minutes = 0.75*60

Time taken = 45secs

Required

constant rate of change of the snail's crawl (speed)

Speed of the snail = distance/time;

Speed of the snail = 0.06/45

Speed of the snail = 0.00133m/s

Hence the constant rate of change of the snail's crawl in m/s is 0.00133m/s

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Solve the equation -9x+1=-x+17

Step2247 [10]

Answer:

x=-2

Step-by-step explanation:

-9x+1=-x+17

Add 9x on both sides:

1=8x+17

Subtract 17 on both sides:

-16=8x

Divide both sides by 8:

-2=x

Check x=-2!

-9x+1=-x+17 with x=-2

-9(-2)+1=-(-2)+17

18+1=2+17

19=19

19=19 is a true equation so x=-2 is correct.

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2 years ago

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Effectus [21]

Answer:

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Step-by-step explanation:

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3 years ago

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Mancini's Pizzeria sells four types of pizza crust. Last week, the owner tracked the number sold of each type, and this is what

Citrus2011 [14]

<em>The complete exercise with the answer options is as follows:</em>

Mancini's Pizzeria sells four types of pizza crust. Last week, the owner tracked the number sold of each type, and this is what he found.

Type of Crust Number Sold

Thin crust 364

Thick crust 240

Stuffed crust 176

Pan style 260

Based on this information, of the next 3000 pizzas he sells, how many should he expect to be thick crust? Round your answer to the nearest whole number. Do not round any intermediate calculations.

Answer:

692 thick crust pizzas

Step-by-step explanation:

With the data given in the exercise, we must first find the total number of pizzas, then we must find the proportion between the thick crust pizzas and the total number of pizzas, finally we must propose a rule of three to find the new proportion of crust pizzas thick on a total of 3000 pizzas.

Type of Crust Number Sold

Thin crust 364

Thick crust 240

Stuffed crust 176

Pan style 260

total pizzas : 1040

Now we must calculate for 3000 pizzas how much would be the total of thick crust pizzas.For that we must use the relationship found, that is, in 1040 pizzas there are 240 thick crust pizzas

1040→240

3000→x

x= $\frac{3000x240}{1040}$ = 692

Now we have a new proportion that out of 3000 pizzas there are a total of 692 thick crust pizzas

3 0

3 years ago

help I will fail math class please help doors for the small cabinets are 11.5 inches long . doors for the large cabinet are 2.3

VARVARA [1.3K]

11.5 * 2.3 = large door size
large door size / 12 = large door size in feet
large door size in feet / 10 = how many large doors can be cut from the board. (you have to round it down if there's a decimal- no 1/2 doors.)

7 0

2 years ago

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$

So, root of the equation =0.205 (Approx)

Approximate relative error

$=\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41$

Approximate relative error in terms of Percentage

=0.41 × 100

= 41 %

7 0

2 years ago