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jeka57 [31]
3 years ago
7

A bouncy ball is dropped. The function h(n)=300(3/4)^n−1 models the maximum height of the ball, in centimeters, after its nth bo

unce.
Select EACH true statement about the scenario.

[] The function represents a geometric sequence.
[] The first term in the sequence is 300.
[] The height of the ball after the first bounce is 300 cm.
[] The ball is dropped from a height of 300 cm.

*Multiple Choice*
Mathematics
1 answer:
lara [203]3 years ago
7 0

The true statements about the scenario are;

  • The function represents a geometric sequence.
  • The first term in the sequence is 300.

The standard form of a geometric sequence is expressed as:

Tn = ar^{n-1}

a is the first term

r is the common ratio

n is the number of terms

Given the expression h(n)=300(\frac{3}{4} )^{n-1}

Compare and contrast

a = 300

This shows that the first term of the sequence is 300.

Also, a function represents a geometric sequence

Hence the true statements about the scenario are;

  • The function represents a geometric sequence.
  • The first term in the sequence is 300.

Learn more here: brainly.com/question/9300199

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Find the total future amount for $500 invested at 3.35% for 4 years compounded monthly.
weeeeeb [17]

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$ 746.16

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7 0
2 years ago
. Last year, at Northern Manufacturing Company, 200 people had colds during the year. One hundred fifty-five people who did no e
Zielflug [23.3K]

Answer:

(a) \frac{1}{5} or 0.2

(b) \frac{1}{10} or 0.1

(c) \frac{3}{10} or 0.3

(d) They are dependent events. See explanation below.

Step-by-step explanation:

Let C = number of employees that had cold = 200

E = number of employees that exercised = 500

(a) P(C) = \dfrac{200}{1000}=\dfrac{1}{5}=0.2

(b) P(C|E)=\dfrac{\text{Number of employees who exercised and had cold}}{\text{Number of employees who exercised}}=\dfrac{50}{500}=\dfrac{1}{10}=0.1

In probability, the notation P(C|E) means the probability of C given that E has occurred. It is given by

P(C|E)=\dfrac{P(C\cap E)}{P(E)}=\dfrac{n(C\cap E)}{n(E)}

(c) P(C|\sim E) denotes the probability of those who did not exercise but had cold. Using the same notations as in (b),

P(C|\sim E)=\dfrac{n(C\cap \sim E)}{n(E)}= \dfrac{150}{500}=\dfrac{3}{10}=0.3

(d) When two events, C and E, are independent, then

P(C\cap E)=P(C)\timesP(E) (This is the multiplication law of probability).

It means, in English, the probability of C and E occurring is equal to the product of the probability of C and the probability of E. From the question,

P(C)=0.2, P(E)=0.5 (since half the employees exercised)

P(C\cap E)=0.05 (It is the ratio of the number of those that exercised and had cold to the total number of employees)

It is seen that

P(C\cap E)\ne P(C)\timesP(E) since

0.05 \ne 0.2\times0.5

7 0
3 years ago
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