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mafiozo [28]
2 years ago
9

Tan9°. tan27°. tan45°. tan72°. tan81°= 1​could u plz solve it with clear process

Mathematics
2 answers:
Inga [223]2 years ago
5 0

<u>Correct</u><u> </u><u>question</u><u>:</u><u>-</u>

<u>Prove </u><u>that </u><u>tan9.</u><u>t</u><u>a</u><u>n</u><u>1</u><u>7</u><u>.</u><u>t</u><u>a</u><u>n</u><u>4</u><u>5</u><u>.</u><u>t</u><u>a</u><u>n</u><u>7</u><u>3</u><u>.</u><u>t</u><u>a</u><u>n</u><u>8</u><u>1</u><u>=</u><u>1</u>

<u>LHS</u>

\\ \sf\longmapsto tan9.tan17.tan45.tan73.tan81

\\ \sf\longmapsto tan9.tan81.tan17.tan73.tan45

\\ \sf\longmapsto tan(90-81).tan81.tan(90-73).tan73.1

\\ \sf\longmapsto cot81.tan81.cot73.tan73

\\ \sf\longmapsto 1.1

\\ \sf\longmapsto 1

balandron [24]2 years ago
5 0

Answer:

Correct question:-

Prove that tan9.tan17.tan45.tan73.tan81=1

LHS

\begin{gathered}\\ \sf\longmapsto tan9.tan17.tan45.tan73.tan81\end{gathered}

⟼tan9.tan17.tan45.tan73.tan81

\begin{gathered}\\ \sf\longmapsto tan9.tan81.tan17.tan73.tan45\end{gathered}

⟼tan9.tan81.tan17.tan73.tan45

\begin{gathered}\\ \sf\longmapsto tan(90-81).tan81.tan(90-73).tan73.1\end{gathered}

⟼tan(90−81).tan81.tan(90−73).tan73.1

\begin{gathered}\\ \sf\longmapsto cot81.tan81.cot73.tan73\end{gathered}

⟼cot81.tan81.cot73.tan73

\begin{gathered}\\ \sf\longmapsto 1.1\end{gathered}

⟼1.1

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