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GREYUIT [131]
3 years ago
5

Does pp taste gooddddd

Mathematics
2 answers:
GrogVix [38]3 years ago
7 0

Answer:

ion know

Step-by-step explanation:

liubo4ka [24]3 years ago
5 0

Answer:

its warm and decent. rate it a 8/10

Step-by-step explanation:

You might be interested in
Factor the algebraic expression 25a + 35
Ronch [10]

Answer:

Ans is 12

Follow me

Good night

7 0
3 years ago
Read 2 more answers
How do i find the following f(x)?? Pls help
Neporo4naja [7]

Answer:

  (a) (f+g)(x) = √(2x) +x²

  (b) (f-g)(x) = √(2x) -x²

  (c) (f·g)(x) = x²√(2x)

  (d) (f/g)(x) = (√(2x))/x²

Step-by-step explanation:

These are all about the meaning of the notation (f <operator> g)(x). When the operator is an arithmetic operation (addition, subtraction, multiplication, division), the notation means the same thing as ...

  f(x) <operator> g(x)

__

(a) (f+g)(x) = f(x) + g(x)

  (f+g)(x) = √(2x) +x²

__

(b) (f-g)(x) = f(x) -g(x)

  (f-g)(x) = √(2x) -x²

__

(c) (f·g)(x) = f(x)·g(x)

  (f·g)(x) = x²√(2x)

__

(d) (f/g)(x) = f(x)/g(x)

  (f/g)(x) = (√(2x))/x²

3 0
4 years ago
-2x-9y=-25 -4x-9y=-23<br> I need there to be a step-by-step explanation of how you solved it.
madreJ [45]

solved what I didn't solve anything

4 0
3 years ago
Can anyone help with my algebra 1 homework??
Anni [7]

Answer:

I believe the final answer is x=3

Step-by-step explanation:

when trying to solve equations, always sort things out and prioritize things, that way it's easier to get to the final answer.



x+2x-5=4

3x-5=4 just move the -5 to the other side and make it a positive

3x=9

x+y=4

y=1

3+1=4



3 0
3 years ago
Suppose that $p$ and $q$ are positive numbers for which \[\log_9 p = \log_{12} q = \log_{16} (p + q).\] what is the value of $q/
SVEN [57.7K]

Given p,q>0 and \log_9p=\log_{12}q=\log_{16}(p+q)=x (say).

Then,

p=9^x\\ q=12^x\\ p+q=16^x

From the above 3 equations,

\frac{q}{p} =(\frac{12}{9} )^x\\ \frac{q}{p} =(\frac{4}{3} )^x\\ \frac{p+q}{p} =(\frac{16}{9} )^x\\ \frac{p+q}{p} =(\frac{4}{3} )^{2x}\\

From the equations, we get

\frac{p+q}{p}=(\frac{q}{p})^2\\ 1+\frac{q}{p}=(\frac{q}{p})^2\\ (\frac{q}{p})^2-\frac{q}{p}-1=0\\ \frac{q}{p}=\frac{1 \pm \sqrt{5}}{2}

Since p,q>0, the negative value is rejected.

\frac{q}{p}=\frac{1 + \sqrt{5}}{2}

3 0
4 years ago
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