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3 years ago

My did Alexander Hamilton cross the rode

2 answers:

katrin2010 [14]3 years ago

3 0

Answer: His son was on the other side. Also, Washington was watching on the other side. And Laurens was on the other side.

Step-by-step explanation:

ruslelena [56]3 years ago

3 0

So he could be shot and have no mates

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a ramp 29 ft long rises to a platform. the bottom of the platform is 20 ft from the foot of the ramp. find x, the angle of eleva

Simora [160]

We will be using the cosine function to figure this out.
The ramp, ground, and platform form a right triangle.
The hypotenuse is 29, and the side adjacent to ∠x is 20.
SO:
Cos ∠x = 20/29
Cos ∠x = 0.68965517241379

Use the function on your calculator to find what angle has a Cos of 0.6896551
Cos 0.6896551 = 46.397°

ANSWER: the angle of elevation is 46.4°

Hope this helps! God bless. :)

3 0

4 years ago

Triangle MNO is an equilateral triangle with sides measuring 16 StartRoot 3 EndRoot units. Triangle M N O is an equilateral tria

Lesechka [4]

Answer:

The correct option is second one i.e 24 units.

Therefore the height of the triangle is

$NR=24\ units$

Step-by-step explanation:

Given:

An equilateral triangle has all sides equal.

ΔMNO is an Equilateral Triangle with sides measuring,

$NM = MO = ON =16\sqrt{3}$

NR is perpendicular bisector to MO such that

$MR=RO=\dfrac{MO}{2}=\dfrac{16\sqrt{3}}{2}=8\sqrt{3}$ .NR ⊥ Bisector.

To Find:

Height of the triangle = NR = ?

Solution :

Now we have a right angled triangle NRM at ∠R =90°,

So by applying Pythagoras theorem we get

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

Substituting the values we get

$(MN)^{2} = (MR)^{2}+(NR)^{2}\\\\(16\sqrt{3})^{2}=(8\sqrt{3})^{2}+(NR)^{2}\\\\(NR)^{2}=768-192=576\\Square\ rooting\ we\ get\\NR=\sqrt{576}=24\ units$

Therefore the height of the triangle is

$NR=24\ units$

6 0

3 years ago

Read 2 more answers

Find the function of ğ...<br>does anybody knows?

Basile [38]

If we let g(x) = x + 2, then
${(x + 2)}^{2} + 2 = ( {x}^{2} + 4x + 4) + 2 \\ = {x}^{2} + 4x + 6$
Of course if we let f(x) = x + 2, then

7 0

3 years ago

According to a certain golf association, the weight of the golf ball shall not be greater than 1.620 ounces (45.93 grams). The

evablogger [386]

Missing Part of Question

d. Refer to part c . If x has a binomial distribution, then so does the number, y , of balls in the sample that meet the USGA’s minimum diameter. [ Note: x + y = 60 ] Describe the distribution of y . In particular, what are p, q , and n ? Also, find E(y) and the standard deviation of y .

Answer:

c. Mean = 12

Standard Deviation = 3.098

n = 60

p = 0.8

q = 0.2

Mean = 48

Standard Deviation = 3.098

Step-by-step explanation:

You've answered a and b part of the question, already.

See extracts below

------------------- Answered to Question a and b begins here

"a. What assumptions must be made in order to use the binomial probability distribution to calculate the probability that a particular kind of golf ball will be removed?

A. The experiment consists of n identical trials. There are only two possible outcomes on each trial. The probability of success can change from trial to trial. The trials are dependent.

B. The experiment consists of n identical trials. There are only two possible outcomes on each trial. The probability of success remains the same from trial to trial. The trials are independent.

C. The experiment consists of n identical trials. The number of outcomes can vary. The probability of success can change. The trials are independent.

b. What information must be known in order to use the binomial probability distribution to calculate the probability that a particular kind of golf ball will be removed?

A. The percentage of that kind of golf ball that meets all the requirements

B. The percentage of that kind of golf ball that meets the size requirements

C. The percentage of that kind of golf ball that meets the velocity requirements

D. The percentage of that kind of golf ball that fails to meet both size and velocity requirements

--------------------------- Answer to Question a and b stops here

I'll continue from c and then proceed to d..

Mean is calculated by np

where n = number of observation i.e. sample size = 5 dozens = 5 * 12 = 60

p = probability of success = 20% = 0.2

Mean, E(x) = 0.2 * 60 = 12

Standard Deviation is calculated by the SquareRoot of the products of mean by q (

Standard Deviation = √npq

Where q = 1 - p

q = 1 - 0.2

q = 0.8

Standard Deviation = √(12)(0.8)

Standard Deviation = √9.6

Standard Deviation = 3.098386676965933

Standard Deviation = 3.098 ----- Approximated

From (c) above,

x represents the number of balls that didn't meet USGA minimum diameter

And y represents the number of balls that meet USGA minimum diameter

In total, there are 5 dozen balls

So, x + y = 5 * 12

x + y = 60

So, n = x + y = 60

p, the probability of success of y is the complement of the probability of success of x.

i.e. p of y = 1 - 0.2

p = 0.8

q = 1 - 0.8 = 0.2

Mean is calculated as

E(Y) = np = 60 * 0.8 = 48

Standard Deviation = √npq

Standard Deviation = √(60 * 0.8 * 0.2)

Standard Deviation = √9.6

Standard Deviation = 3.098386676965933

Standard Deviation = 3.098 ----- Approximated

6 0

4 years ago

Simplify the expression please

Taya2010 [7]

Answer:

-10/-12

Step-by-step explanation:

5 0

3 years ago