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katrin [286]
4 years ago
10

What is the tenth term of the sequence 2, 5, 8, 11, 14, … ?

Mathematics
2 answers:
nikitadnepr [17]4 years ago
7 0
The tenth term is 29 :)
ziro4ka [17]4 years ago
4 0
<span>Every term is adding 3 to the previous term. Therefore, the terms are 2, 5, 8, 11, 14, 17, 20, 23, 26, 29 ... The tenth term is 29.</span>
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Two angles are comlementary. the first angle measures x and the second angle measures 3x-10. find x?
ryzh [129]
X=25

4x-10=90
Add 10 to both sides
4x=100
Divide both sides by 4
6 0
3 years ago
Angle A and angle B are supplementary angles. If m angle A = (5x+2) and m angle B = (8x+9) , then find the measure of angle B
otez555 [7]
You first identify what supplementary angles are,angles that add up to 180.
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x=169divided by 17
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8 0
3 years ago
29,27,24,20,15... whats next
hodyreva [135]
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Read 2 more answers
Estimates of the number of cells in the human body vary over an order of magnitude.​ Indeed, the precise number varies from one
Amiraneli [1.4K]

Answer:

a) 2.00 × 10¹⁰;  b) 2.00 × 10¹³

Step-by-step explanation:

a) No. of cells in 1 cm³

\text{No. of cells} =\text{1 cm}^{3} \times\left( \dfrac{\text{1 m}}{\text{100 cm}}\right )^{3} \times \left (\dfrac{1 \, \mu \text{m} }{10^{-6}\,\text{ m}}\right )^{3} \times  \dfrac{\text{1 cell}}{\text{50 $\,\mu$m}^{3}} = \mathbf{2.00 \times 10^{10}} \textbf{ cells}

b) No. of cells in 1 L

\text{No. of cells} =  \text{1 L} \times \dfrac{\text{1000 cm}^{3}}{\text{1 L}} \times \dfrac{2 \times 10^{10} \text{ cells}}{\text{1 cm}^{3}} = \mathbf{2.00 \times 10^{13}} \textbf{ cells}

7 0
3 years ago
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Sergio039 [100]

Answer:

D. y=-2x+4

Step-by-step explanation:

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