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oee [108]
2 years ago
8

100 points

Mathematics
1 answer:
mylen [45]2 years ago
3 0

Answer:127

all you do is subtract -70 by 57 and it will give you a negative but get rid of it and you get 127 or just take the - away from -70 and add 57

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What value of Y will satisfy the given equation y divided by 2y — 15 = 7/5​
guapka [62]

Answer:

\huge\boxed{\sf y = \frac{41}{5}  \ OR \ y = 8\frac{1}{5} }

Step-by-step explanation:

\sf 2y-15 = \frac{7}{5} \\\\Adding \ 15 \ to \ both \ sides\\\\2y = \frac{7}{5} + 15\\\\2y = \frac{7+75}{5} \\\\2y = \frac{82}{5} \\\\Dividing \ both \ sides \ bu 2\\\\y = \frac{82}{5*2} \\\\y = \frac{41}{5}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
3 0
3 years ago
Solve for Q<br> Q/B + A = Y
Otrada [13]
What are the numbers that are supposed to be plugged in?

6 0
3 years ago
For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
3 years ago
Find two pairs of integers whose sum is -6
aalyn [17]
<span>Find all pairs of consecutive even integers whose sum is greater than 73 but less than 79.

</span>
6 0
3 years ago
Read 2 more answers
Select True or False for each statement.
mote1985 [20]
<h2>Answer:</h2>

For a real number a, a + 0 = a.  TRUE

For a real number a, a + (-a) = 1.  FALSE

For a real numbers a and b, | a - b | = | b - a |.  TRUE

For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c).  FALSE

For rational numbers a and b when b ≠ 0, is always a rational number. TRUE

<h2>Explanation:</h2>

  • <u>For a real number a, a + 0 = a.  </u><u>TRUE</u>

This comes from the identity property for addition that tells us that<em> zero added to any number is the number itself. </em>So the number in this case is a, so it is true that:

a+0=a

  • For a real number a, a + (-a) = 1.  FALSE

This is false, because:

a+(-a)=a-a=0

For any number a there exists a number -a such that a+(-a)=0

  • For a real numbers a and b, | a - b | = | b - a |.  TRUE

This is a property of absolute value. The absolute value means remove the negative for the number, so it is true that:

\mid a-b \mid= \mid b-a \mid

  • For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c).  FALSE

This is false. By using distributive property we get that:

(a + b)(a + c)=a^2+ac+ab+bc \\ \\ a^2+ab+ac+bc \neq a+(b.c)

  • For rational numbers a and b when b ≠ 0, is always a rational number. TRUE

A rational number is a number made by two integers and written in the form:

\frac{u}{v} \\ \\ v \neq 0

Given that a \ and \ b are rational, then the result of dividing them is also a rational number.

7 0
3 years ago
Read 2 more answers
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