Notice that
11/12 = 1/6 + 3/4
so that
tan(11π/12) = tan(π/6 + 3π/4)
Then recalling that
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
⇒ tan(x + y) = (tan(x) + tan(y))/(1 - tan(x) tan(y))
it follows that
tan(11π/12) = (tan(π/6) + tan(3π/4))/(1 - tan(π/6) tan(3π/4))
tan(11π/12) = (1/√3 - 1)/(1 + 1/√3)
tan(11π/12) = (1 - √3)/(√3 + 1)
tan(11π/12) = - (√3 - 1)²/((√3 + 1) (√3 - 1))
tan(11π/12) = - (4 - 2√3)/2
tan(11π/12) = - (2 - √3) … … … [A]
Answer:
find derivative of function
sub in x value of point to find gradient of tangent
put gradient into y=(gradient)x+c
Sub in point and solve for c
you have found the equation of the tangent.
Answer:
Step-by-step explanation:
Using soh cah toa
Sin=opp/hot
Sin 52°=h/121
h=sin52°×121
h=0.7880×121feet
h=95.348feet
1. The area of a circle is
The area is 9.07 cm^2.
2. The volume of a cube is
The volume is 91.125 m^3
