1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lesechka [4]
3 years ago
7

Random Weirdos Unite, 'm bored ._.

Mathematics
2 answers:
tresset_1 [31]3 years ago
4 0

Answer:

Same here.

Step-by-step explanation:

I'm usually bored, that's why I mainly use this site.

:D

spayn [35]3 years ago
3 0

Answer:

Step-by-step explanation:

Im not eva gonna be a wierd IM A BESHTIE

But im still in the hospital -_-

You might be interested in
Evaluate using the order of operations ( 8/9 - 1/3) x 2/3
Korvikt [17]
(8/9-3/9)*2/3=5/9*2/3=10/27
4 0
4 years ago
Read 2 more answers
1000000000000000000000000000000000000000000000X100/1/222X1
jok3333 [9.3K]

Answer:

4.5045045 x 10^44

Step-by-step explanation:

I just put it into a calculator idk if its even right

5 0
3 years ago
A random sample of 84 students at a university showed an average age of 22 years and a sample standard deviation of 3 years. Fin
Debora [2.8K]

Answer:

The margin of error for the 94% confidence interval is 0.6154.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error of this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 94% confidence level is, <em>z</em> = 1.88.

Compute the margin of error for the 94% confidence interval as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

          =1.88\times\frac{3}{\sqrt{84}}\\\\=0.6154

Thus, the margin of error for the 94% confidence interval is 0.6154.

7 0
3 years ago
From least to greatest 2.3, 2 4/5, 2.6
algol [13]
2.3, 2.6, 2 4/5

2 4/5= 2.8
7 0
3 years ago
In a particular year, a total of 50,127 students studied in two of the most popular host countries when traveling abroad. If 838
Arlecino [84]

Answer:

In the most popular abroad country: 29,255 students

In the second-most one: 20,872 students

Step-by-step explanation:

Let's write the situation in an equation to help us solve this. X represents the amount of students in the second most popular country. So we know that in total, there's 50,127 students so let's make an equation that equals this. ???????=50,127. As we know, the most popular country has 8383 more students than the second one so we can write it as x+8383 and for the second most popular country, we can write it as x. We know that both of the countries students combined equal 50,127 students so we have our equation. (x)+(x+8383)=50,127 students. After solving the equation, you get x=20, 872. As we know x=the amount of students in the second most popular country which means there's 20,872 students in the second one. Additionally, for the first most popular one, the equation for the amount of students in it is x+8383 so..... 20,872+8383=Total number of students in the most popular one which is 29,255 students.

7 0
3 years ago
Other questions:
  • Gretchen has 50/100/50 liability insurance with a $500 deductible. While parked on the street,another car hits hers and then lea
    14·1 answer
  • A circle with a radius of 1 unit​
    5·1 answer
  • A movie rental company charges a yearly membership fee of $18.Each movie rental is $1.50.Which equation could be used to find th
    8·1 answer
  • What is 12 dived by 2/3​
    7·2 answers
  • Find the measure of the indicated angle to the nearest degree.
    6·1 answer
  • Carli has 4 1/2 walls left to paint in order for all the bedrooms in her house to have the same color paint. However, she has us
    8·1 answer
  • Ano ang fraction ng 1.5​
    10·1 answer
  • Tomas is a commercial real estate agent who earns a yearly salary of $82,500 and a 2.
    6·1 answer
  • Will give BRAINLEST :)
    7·1 answer
  • ====MATH QUESTION====Extra points
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!