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2 years ago

The following are quiz scores: 85, 88, 89, 96, 91, 77, 79, 98, 86, 99. What is the standard deviation of the given test scores?

Mathematics

1 answer:

ArbitrLikvidat [17]2 years ago

5 0

Answer:

7.1

Step-by-step explanation:

- Find mean

- For each number you subtract the mean and square the result.

- Work out the mean of those squared differences and find square root of that.

- Hope that helped! Let me know if you need further explanation.

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A commercial fisherman is (less likely, equally likely, more likely) to need health insurance than a supermarket employee.

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Answer:

A commercial fisherman is

EQUALLY LIKLEY

to need health insurance than a supermarket employee.

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to need health insurance than a nonsmoker.

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2 years ago

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3 years ago

1. A bag of marbles has 15 marbles in it. there are 7 Red marbles and 8 Green marbles. What is the ratio probability of pulling

elixir [45]

Answer:

pulling red 7:15

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3 0

3 years ago

Read 2 more answers

Please help me with this question. Please!

erica [24]

150=i^2
150^.5=12.2474
11^2=121
12^2=144
13^2=169
between 12 and 13, D

8 0

3 years ago

A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6

ddd [48]

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

<u>Now, According to question</u>

The population of bacteria after 6 days = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, f = i × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, f = 1000 × $(1+\dfrac{\textrm 15}{100})^{\textrm 6}$

Or, f = 1000 × $(1.15)^{6}$

Or, f = 1000 × 2.31306

∴ f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06 Answer

3 0

3 years ago