All categories

2 years ago

The following are quiz scores: 85, 88, 89, 96, 91, 77, 79, 98, 86, 99. What is the standard deviation of the given test scores?

Mathematics

1 answer:

ArbitrLikvidat [17]2 years ago

5 0

Answer:

7.1

Step-by-step explanation:

- Find mean

- For each number you subtract the mean and square the result.

- Work out the mean of those squared differences and find square root of that.

- Hope that helped! Let me know if you need further explanation.

You might be interested in

What is the value of xy/z if x=-2 and z=4

CaHeK987 [17]

(-2)(y)/4

What is the value of y, I think this is missing to figure out the final answer.

But once y is known you will use the xy/z gormils. Multiply -2 and y value. Then divide that by 4.

Please vote my answer brainliest. thanks!

7 0

3 years ago

Please help I need for graph

Gala2k [10]

For a you will see a bar graph and the dependent o think would be bird species

3 0

2 years ago

Neeeeed helpppppp please

MissTica

Answer:

Scale factor = 7

Step-by-step explanation:

Dilation with scale factor to map HEFG to DABC will be,

Scale factor = $\frac{\text{Dimension of Image DABC}}{\text{Dimension of preimage HEFG}}$

= $\frac{\text{Length of CD}}{\text{Length of GH}}$

Length of CD = Distance between two points C(0, -7) and D(-7, 0)

= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

= $\sqrt{(-7-0)^2+(0+7)^2}$

= $\sqrt{98}$

= $7\sqrt{2}$

Length of GH = Distance between G(0, -1) and H(-1, 0)

= $\sqrt{(-1-0)^2+(0+1)^2}$

= $\sqrt{2}$

Scale factor = $\frac{7\sqrt{2} }{\sqrt{2} }$

= 7

6 0

2 years ago

!! 100 POINTS SELECTED AND BRAINLIEST!!

vredina [299]

Answer:

Secants – 1. <CBG 2. <AGF 3. <ABD

Tangent – 1. <CDE

Chords – 1. <BD 2. <DF 3. <BG 4. <BF 5. <GD 6. <FG

Angles – 1. 45 2. 75 3. 35 4. 70 5. 75 6. 55 7. 50 8. 25 9. 35 10. 70 11. 50 12. 25 13. 70 14. 50. 15. 60 16. 85 17. 95 18. 85 19. 95

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago