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Hoochie [10]
2 years ago
13

Last year, Felipe invested his money in two purchases. He purchased a certificate of deposit for $12,000 that paid 6% interest p

er year and purchased $4000 in corporate bonds paying 5% interest per year. Answer the questions below.
Do not do any rounding.
(a) What was the total interest earned at the end of 1 year?
$
(b) What was the percent interest for his total investment?
%
Mathematics
1 answer:
Alexus [3.1K]2 years ago
8 0
Same as the other one

part A)

CD 12,000 at 6%, how much is that?  (6/100) * 12000

CB 4000 at 5%, how much is that?  (5/100) * 4000

part B)

total investment was 12000 + 4000 = 16000

the earned interest above are 720 and 200 respectively

total yield was, 720 + 200 = 920

if 16000 is the 100%, how much is 920 in percentage?

\bf \begin{array}{ccllll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
16000&100\\
920&x
\end{array}\implies \cfrac{16000}{920}=\cfrac{100}{x}

solve for "x"
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Question:- Alana biked 12 miles in 48 minutes. What is Alana's speed in miles per minute?

Answer:-

Set up a proportion.

12/48 = 1/x

Cross multiply.

12*x = 12x
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3 years ago
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trasher [3.6K]

Answer:

a) 0.3571

b) The p-value is 0.362007.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 1.35

Sample mean, \bar{x} = 1.4

Sample size, n = 26

Alpha, α = 0.01

Sample standard deviation, s = 0.7

First, we design the null and the alternate hypothesis

H_{0}: \mu = 1.35\text{ entrees per order}\\H_A: \mu > 1.35\text{ entrees per order}

We use One-tailed t test to perform this hypothesis.

a) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n-1}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{1.4 - 1.35}{\frac{0.7}{\sqrt{25}} } = 0.3571

b) The p-value at t-statistic 0.3571 and degree of freedom 25 is 0.362007.

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