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Marrrta [24]
2 years ago
8

Someone help plsss i don’t understand these are my last points no one doesn’t answer my question

Mathematics
2 answers:
LenaWriter [7]2 years ago
6 0

Answer:

1. y would be 0 and x is 6 : (6,0)

   I cant really see the graphs clearly. I hope this helps.

2. I can help you with the second one I'm sorry there isn't enough information.

Step-by-step explanation:

UkoKoshka [18]2 years ago
3 0

Answer:

for 1 it is the 3rd graph

Step-by-step explanation:

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You receive a report that to demand for lawn care services (demand) will grow from $900,000 per year to $990,000 and the availa
storchak [24]

Answer: The answer is supply.

Step-by-step explanation:

I just took the test for it.

5 0
2 years ago
Read 2 more answers
Brainliest + Points!
LenaWriter [7]
Hey refer to attachment!!!

Draw straight line from 220 (in thousands ) to the plotted line. Draw line parallel to x-axis from point where it touches the plotted line to the y -axis.

It'll automatically meet at 500 which is the answer..

All you need to do is to see the graph carefully.

Hope it helps *_*

3 0
3 years ago
Find the equation of a circle with a center at (0, -4) and a point on the circle is (6, 0).
EastWind [94]

Answer:

x^2 + ( y + 4)^2 = 52

Step-by-step explanation:

Equation of circle with center (a , b) and radius, r is :

(x -a)^2 + ( y -b)^2 = r^2

Given :  a = 0 , b = - 4

Step 1 : Find the radius.

       Given ( 6 , 0 ) lies on the circle. Therefore the distance between the center (0 , - 4) of the circle and ( 6 , 0 ) gives the radius of the circle.

   r = \sqrt{( 0 - 6)^2 + ( -4 - 0)^2} \\\\

     = \sqrt{ 36 + 16 } \\\\= \sqrt{52}

Step 2 : Equation of circle.

  (x - 0)^2 + (y -( - 4))^2 = (\sqrt{52})^2\\\\x^2 + ( y+ 4)^2 = 52

8 0
2 years ago
2 times 2.1-(2.8 times 1.5)
natali 33 [55]
The simplest answer is 0 if u actrually do the work if u have to sneak a calculator in XD

5 0
3 years ago
Show me a order line 3/10,0.5 ,1/5 greater to the least
Svetradugi [14.3K]
1/5 , 3/10 , 0.5
This will help
5 0
3 years ago
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