All categories

3 years ago

Twice the difference between six times a number and three

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

8 0

The answer is: 2-6x+3x

Naya [18.7K]3 years ago

6 0

Let "a number", be x

six times a number = 6x

difference between 6x and three = 6x - 3

twice the " " = 2(6x - 3)

2(6x - 3) is your expression.

hope this helps

You might be interested in

Consider the triangle.

BigorU [14]

Answer:

It's the second answer down : Angle B, A and C

Step-by-step explanation:

7 0

3 years ago

The reflexive property of congruence allows you to say that RST=____

weqwewe [10]

Answer:

The reflexive property of congruence allow us to say that RST = RST .

Option (C) is correct .

Step-by-step explanation:

Definition of Reflexive Property of congurence

The meaning of Congruence is figure has the same size and shape. If you were comparing something to itself, then it definitely have the same size and shape this is called Reflexive Property of congurence .

By using Reflexive property of congurence .

RST = RST

Therefore reflexive property of congruence allow us to say that RST = RST .

Option (C) is correct .

7 0

3 years ago

Read 2 more answers

Explain the steps you would take to write 36/10 as a decimal

kherson [118]

You just have to make 36/10 into 3 6/10. After that, it would become 3.6

4 0

3 years ago

Read 2 more answers

For what positive values of k does the function y=sin(kt) satisfy the differential equation y''+144y=0 ?

lina2011 [118]

Answer:

The positive value of k that the function y = sin(kt) satisfies the differential equation y'' + 144y = 0 is +12

Step-by-step explanation:

To determine the positive values of k that the function y = sin(kt) satisfy the differential equation y''+144y=0.

First, we will determine y''.

From y = sin(kt)

y' = $\frac{d}{dt}(y)$

y' = $\frac{d}{dt}(sin(kt))\\$

y' = kcos(kt)

Now for y''

y'' = $\frac{d}{dt}(y')$

y'' = $\frac{d}{dt}(kcos(kt))$

y'' = $-k^{2}sin(kt)$

Hence, the equation y'' + 144y = becomes

$-k^{2}sin(kt)$ + $144(sin(kt))$ $= 0$

$(144 - k^{2})(sin(kt)) = 0$

$(144 - k^{2})= 0$

∴ $k^{2} = 144\\$

$k =$ ± $\sqrt{144}\\$

$k =$ ± $12$

∴ $k = +12$ or $-12$

Hence, the positive value of k that the function y = sin(kt) satisfies the differential equation y'' + 144y = 0 is +12

7 0

3 years ago

H(n)=n^2-1; find h(4)

LiRa [457]

Answer:

h(4)=4²-1

=16-1

=15

hope it helps.

7 0

3 years ago

Read 2 more answers