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liberstina [14]
3 years ago
6

Twice the difference between six times a number and three

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0

The answer is: 2-6x+3x

Naya [18.7K]3 years ago
6 0

Let "a number", be x

six times a number = 6x

difference between 6x and three = 6x - 3

twice the " " = 2(6x - 3)

2(6x - 3) is your expression.

hope this helps

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The graph of a system of parallel lines will have no solutions.
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7 0
3 years ago
the hypotenuse of a right triangle has a length of 13cm the longer of the two legs is 7cm longer than the shorter leg
Margarita [4]

Let's say the shorter side is x.

So, the longer side would be ( 7 + x )

Now we have to use the Pythagorean Theorem to find the value of x.


a² + b² = c²

( 7 + x )² + x² = 13

7² + x² + x² = 13²

49 + 2x² = 169

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x² = 60

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So the longer side is ( 7 + √60 ) and the shorter side is √60


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3 years ago
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5 0
3 years ago
Math quest after a winter storm, the depth of the snow on cherry street was 10 \text{ cm}10 cm10, space, c, m. but then, the sno
Zanzabum

Answer:

9 cm.

Step-by-step explanation:

Let x be the number of hours.

We have been given that after a winter storm, the depth of the snow on cherry street was 10 cm. Then, the snow started melting at a rate of \frac{1}{3}, so the snow melted in x hours will be \frac{1}{3}x.

Since initially there was 10 cm of snow, so the depth of snow after x hours will be:

10-\frac{1}{3}x

To find the depth of snow after 3 hours we will substitute x=3 in our expression.

10-\frac{1}{3}\times 3

10-1

9

Therefore, the depth of the snow on cherry street after 3 hours will be 9 cm.

3 0
3 years ago
Read 2 more answers
Let omega be a complex number such that omega^3 = 1. Find all possible values of {1}{1 + \omega} + {1}{1 + \omega^2}. Enter all
Norma-Jean [14]

Answer:

1 is Answer.

Step-by-step explanation

\frac{1}{1+omega^{2} } + \frac{1}{1+omega }\\

= \frac{(-1)*(omega + 1)}{omega^{2}  }

As we know that ω²+ω+1=0

Thus putting in above equation, we get

= \frac{1}{(-1)*omega } + \frac{1}{(-1)*omega^{2}  }

Rearranging and simplifying:

= \frac{-1}{omega } + \frac{-1}{omega^{2}  }

= \frac{(-1)*(omega + 1)}{omega^{2}  }

= \frac{(-1)*(- omega^{2} )}{omega^{2}  }

= 1 Answer

8 0
3 years ago
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