Use function notation to represent each statement. Six hours after it started raining, the amount of rain was 37 millimeters.

An irrational number between 5/7 and 7/9 is?

Alex17521 [72]

Answer:

Step-by-step explanation:

-----------

5/7 can be written as 0.714285

-----

7/9 can be written as 0.777

∴ An irrational number between 5/7 and 7/9 is 0.72010010001.....

or u ca write other numbers also like

0.73010203.....

0.74090080007.....

7 0

3 years ago

Find the number of distinct arrangements of the 9 letters in SEVENTEEN. Two of the same letter are considered identical (not dis

Bess [88]

........54..............

8 0

3 years ago

Helppppppppppppppppppppppp please

baherus [9]

Answer:

A

Step-by-step explanation:

Two Squares

There are 2 squares at the top and bottom. All sides = 3

2* s^2

2 * 3^2

2 * 9

18

Middle Figure.

<u>Triangles</u>

There are many ways to solve this. I think the most easily understood is to break it into 2 triangles and a rectangle.

Base of both triangles = 5 + 5 = 10

The height of each triangle = (7 - 3)/2 = 4/2 = 2. You divide by 2 because there are 2 bases -- one in each triangle.

Area = 1/2 * 2 * 10 = 10

But there are 2 of them so the total area is 20

<u>Rectangle</u>

The length of the rectangle = 5 + 5 = 10

The width = 3

Area = 30

Total

Total Area = 2 squares + 2 triangles + 1 rectangle

Total Area = 18 + 20 + 30 = 68

8 0

3 years ago

If you understand, please put the answer!

il63 [147K]

Step-by-step explanation:

3-8 is diagnal 7-2 is also 7-2 is the answer

8 0

3 years ago

Describe the translation of the function from the parent function f(x) = x².

kkurt [141]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\

\end{array}\\$

$\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}
$

now, notice the template above... now let's see your function $\bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}$

so.. what do you think was the shift then?

8 0

3 years ago