Explanation:
It is given that,
Radius of curvature of the mirror, R = 1.54 cm
(a) We have to find the focal length of the mirror. The relationship between the focal length and the radius of curvature is given by :
f = focal length of the mirror
f = 0.77 cm
(b) The power of mirror is given by the reciprocal of focal length i.e.
Power, 
P = 1.29 diopters
Hence, this is the required solution.
Answer:
The correct answer is V√5
Explanation:
Let V be the velocity of the satellite orbiting at radius r.
Let V(5r) be the velocity of the satellite orbiting at radius 5r.
Recall:
Escape velocity is given by:
V = √(2gr)
Where V is the escape velocity
g is the acceleration due to gravity
r is the radius of the earth.
With the above equation, we can obtain the answer to the question as follow:
V = √(2gr)
V(5r) = √(2g5r)
Next, we'll obtained the ratio of V(5r) to V as shown below
V(5r) : V => V(5r)/V
V(5r)/V = √(2g5r) / √(2gr)
V(5r)/V = √5
Cross multiply
V(5r) = V√5
From the above illustration, we can see that when the satellite is moved to 3r, then the expression for the velocity will be V√5
Gravitational potential energy is the higher it us above the ground the more gravitational potential energy it holds.Sphere 2 says it has three times the mass of sphere 1. Therefore the answer is Sphere 2 since it was raised three time the mass of sphere 1. and the rest of the answer choices dont make sense.
