Answer:
h' = 603.08 m
Explanation:
First, we will calculate the initial velocity of the pellet on the surface of Earth by using third equation of motion:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity on the surface of earth = - 9.8 m/s² (negative sign due to upward motion)
h = height of pellet = 100 m
Vf = final velocity of pellet = 0 m/s (since, pellet will momentarily stop at highest point)
Vi = Initial Velocity of Pellet = ?
Therefore,
(2)(-9.8 m/s²)(100 m) = (0 m/s)² - Vi²
Vi = √(1960 m²/s²)
Vi = 44.27 m/s
Now, we use this equation at the surface of moon with same initial velocity:
2g'h' = Vf² - Vi²
where,
g' = acceleration due to gravity on the surface of moon = 1.625 m/s²
h' = maximum height gained by pellet on moon = ?
Therefore,
2(1.625 m/s²)h' = (44.27 m/s)² - (0 m/s)²
h' = (1960 m²/s²)/(3.25 m/s²)
<u>h' = 603.08 m</u>
Answer:
Energy expenditure in K cals/min = 10 K cals /min (approximately)
Explanation:
As we know
Energy expenditure in Kcal/min= METs x 3.5 x Body weight (kg) / 200
Given is METs=7.6
Weight of Jazz= 172lb=78.02kg
putting the values in formula,
Energy expenditure in K cals/min= 7.6 x 3.5 x 78.02 / 200
=10.38 K cals /min
=10 K cals /min (approximately)
Therefore, Energy expenditure in K cals/min by Jazz will be approximately 10 K cals /min
Answer:
The centripetal force on body 2 is 8 times of the centripetal force in body 1.
Explanation:
Body 1 has a mass m, and its moving in a circle with a radius r at a speed v. The centripetal force acting on it is given by :
Body 2 has a mass 2m and its moving in a circle of radius 4r at a speed 4v. The centripetal force on body 2 is :
So, the centripetal force on body 2 is 8 times of the centripetal force in body 1.
Average v = (initial v + final v)/2
= (14 m/s + 0 m/s)/2
= 7 m/s
Your average velocity during braking is 7 m/s
