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Lerok [7]
3 years ago
11

Calculate the focal length of the mirror formed by the convex side of a shiny spoon that has a 1.54 cm radius of curvature. (b)

What is its power in diopters?
Physics
1 answer:
blondinia [14]3 years ago
6 0

Explanation:

It is given that,

Radius of curvature of the mirror, R = 1.54 cm

(a) We have to find the focal length of the mirror. The relationship between the focal length and the radius of curvature is given by :

R=2f

f = focal length of the mirror

f=\dfrac{1.54\ cm}{2}

f = 0.77 cm

(b) The power of mirror is given by the reciprocal of focal length i.e.

Power, P=\dfrac{1}{f}

P = 1.29 diopters

Hence, this is the required solution.

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VladimirAG [237]

Answer:

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3 0
3 years ago
A plane travels 2.5 KM at an angle of 35 degrees to the ground, then changes direction and travels 5.2 km at an angle of 22 degr
Solnce55 [7]

Answer:

7.7 km 26°

Explanation:

The total x component is:

x = 2.5 cos(35°) + 5.2 cos(22°) = 6.87

The total y component is:

y = 2.5 sin(35°) + 5.2 sin(22°) = 3.38

The magnitude is:

d = √(x² + y²)

d = 7.7 km

The direction is:

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θ = 26°

5 0
3 years ago
A factory has a solid copper sphere that needs to be drawn into a wire. The mass of the copper sphere is 76.5 kg. The copper nee
baherus [9]

Answer:

120.125 m

Explanation:

Density = Mass/volume

D = m/v .............................. Equation 1.

Where D = Density of the solid copper sphere, m = mass of the solid copper sphere, v = volume of the solid copper sphere.

Making v the subject of the equation,

v = m/D............................... Equation 2

Given: m = 76.5 kg,

Constant: D = 8960 kg/m .

Substituting into equation 2

v = 76.5/8960

v = 0.0085379 m³

Since the copper sphere is to be drawn into wire,

Volume of the copper sphere = volume of the wire

v = volume of the wire

Volume of wire = πd²L/4

Where d = diameter of the wire, L = length of the wire.

Note: A wire takes the shape of a cylinder.

v = πd²L/4 ........................ equation 3.

making L the subject of the equation,

L = 4v/πd²..................... Equation 4

Given: v = 0.0085379 m³, d = 9.50 mm = 0.0095  and π = 3.14

Substitute into equation 4

L = 4×0.0085379/(3.15×0.0095²)

L = 0.0341516/0.0002843

L = 120.125 m.

L = 120.125 m

Thus the length of the wire produced = 120.125 m

4 0
3 years ago
The energy of a photon was found to be
Vaselesa [24]

now you can yourself know to which part of electromagnetic spectrum the photon belongs....

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4 0
2 years ago
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Two charged objects have a repulsive force of .80 N. If the charge of one of the objects is doubled, then what is the new force?
sveticcg [70]
The new force would be 1.6 N.
Since the charges multiply as variables (q1)x(q2), then it would simply be double (q1)x(q2), or 1.6.
6 0
3 years ago
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