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Tatiana [17]
2 years ago
5

Hhhhhhhhhhhhhhejifjkrefkrijger

Mathematics
1 answer:
rjkz [21]2 years ago
8 0

Answer:

rawrhh!!!

Step-by-step explanation:

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Can someone help on all three
scZoUnD [109]
1. p=7.50+5.50v
p is the total price, v is the amount of visitors
For 6 visitors, it is $40.50

2. p=100+15x
p is the total price, x is the amount of dinner served
For 20 guests, it is $400

3.c=4.25+3.5p
c is the total cost, p is the amount of additional pecks you choose
For 3 pecks, it is $14.75
5 0
3 years ago
Rhonda is painting four pictures on paper. She has 1/8 of a gallon of paint to paint all the pictures. How much paint will she u
Doss [256]

Answer:

1/32

Step-by-step explanation:

To determine the amount of paint she would use for a picture, divide the total gallon of paint by the number of pictures

Paint she would use for one painting = total gallons of paint / number of pictures

1/8 ÷ 4

= 1/8 x 1/4

= 1/32

3 0
3 years ago
Find the missing side length, and enter your answer in the box below. If
Zigmanuir [339]

Answer:

2.5

Step-by-step explanation:

If you know two other sides of the right triangle, it's the easiest option; all you need to do is apply the Pythagorean theorem:

a² + b² = c²

if leg a is the missing side, then transform the equation to the form when a is on one side, and take a square root:

a = √(c² - b²)

if leg b is unknown, then

b = √(c² - a²)

for hypotenuse c missing, the formula is

c = √(a² + b²)

4 0
3 years ago
Use the distributive property to write an expression that is equivalent to the sum of 9 and 54.
xenn [34]

Answer:

9(1 +6)

Step-by-step explanation:

9 = 9 * 1

54 = 9 * 6

9 + 54 = (9*1 ) + (9*6)      {9 is common in both terms}

           = 9*(1 + 6)

7 0
3 years ago
The half-life of cesium-137 is 30 years. Suppose we have a
VMariaS [17]
(a) If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) e^{kt}=100e^{kt}.

y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\
y(t) = 100e^{-(\ln 2)t/30} = 100 \cdot 2^{-t/30}

(b) y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}

(c)
100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\
t = -30 \frac{\ln 0.01}{\ln 2} \approx \text{199.3 years}
 
3 0
3 years ago
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