30 weeks because
If p(x)=x3-3x2,then find the value of p(1)
2 answers:
Answer:
p=-3x
Step-by-step explanation:
Divide each term by x
Simplify the left side
Cancel the common factor of x
Cancel the common factor
Divide p by 1
Simplify the right side
Simplify each term
Cancel the common factor of x^3 and x
Factor x out of x^3
Cancel the common factors
Raise x to the power of 1
Factor x out of x^1
Cancel the common factor
Rewrite the expression
Divide x^2 by 1
Cancel the common factor of x^2 and x
Factor x out of −3x^2
Cancel the common factors
Raise x to the power of 1
Factor x out of x^1
Cancel the common factor
Rewrite the expression
Divide −3x by 1
p=x^2−3x
You might be interested in
Given polynomial function:
.
We need to apply Descartes' rule of sign to identify the number of complex roots.
The given polynomial is f(x)=x^3-96x^2+400
Let us see the number of sign changes in f(x)
There are 2 sign changes in f(x). One from plus to minus and second from plus to minus. Hence, there 2 or 0 positive roots.
Now, let us see the number of sign changes in f(-x)
f(-x)=-x^3-96x^2+400
There are only one sign change. Hence, there will be 1 negative roots.
The degree of the polynomial is 3.
Hence, there will be exactly 3 zeros.
<em>Therefore, the possible numbers of zeros are:</em>
<em>2 positive, 1 negative and 0 complex</em>
<em>0 positive, 1 negative and 2 complex.</em>
Let us see the graph:
In the graph, we can see that the graph cuts the x axis at three points (2 positive, 1 negative points).
<h3>Hence, the number of complex zeros for the given polynomial is zero.</h3>