D =√(x2-x1)^2 + (y2-y1)^2
......._____________
5 =√(3-0)^2 + (k-1)^2
.......__________
5 =√3^2 + (k-1)^2
25 = 9 + (k-1)^2
16 = k^2 - 2k + 1
k^2 -2k - 15 = 0
(k - 5)(k + 3) = 0
k - 5 = 0.....or.......(k + 3) = 0
k = 5.........or.......k = -3
(3d^2 - 10d) = d(3d - 10).
Answer:
x=8
Step-by-step explanation:
x=5+3
= 8
Answer:
The one furthest to the right.
Answer:
x = -59/4
Step-by-step explanation:
3 x+ 2 = -x-57
Add x to each side
3 x+x+ 2 = -x+x-57
4x+2 = -57
Subtract 2 from each side
4x +2-2 = -57-2
4x = -59
Divide each side by 4
4x/4 = -59/4
x = -59/4
