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2 years ago

15

Maria spends $14 on lottery tickets every week and spends $140 month on food.

2 answers:

kozerog [31]2 years ago

8 0

Ten percent is the answer

pantera1 [17]2 years ago

6 0

Your answers is supposed to be 10%

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What is the next number in the sequence below.<br> 216, 72, 24,

tiny-mole [99]

The next number in the sequence is 8

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2 years ago

60 + 60 × 0 + 1 = Solve this

belka [17]

61 because you always multiply first 60 x 0= 0 so now we have 60+1 which is 61

5 0

2 years ago

Read 2 more answers

san4es73 [151]

Step-by-step explanation:

<u>Step 1: Determine an ordered pair</u>

A solution of an equation just means that the point lies on the line. We can find any y-value when we plug in a specific x-value. For example, if we want to know what ordered pair lies at x=1, we just plug in y = -1/2(1) and solve for y which gives us -1/2. This gives us an ordered pair of (1, -1/2). We can continue to do this for any x value.

We can also reverse the order and plug in the y-value and get the x-value in order to accomplish the same goal but it's a bit harder.

Hope this helps!

6 0

1 year ago

Read 2 more answers

Read the problem and examine the diagram. 14 students in Neil's class play basketball.35 % of the students in his class play bas

Nina [5.8K]

The answer is

C.The answer should be 35% of 14

4 0

3 years ago

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

2 years ago