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Nataliya [291]
2 years ago
7

Help pls I’m desperate

Mathematics
1 answer:
notka56 [123]2 years ago
8 0

Answer:

1. to find the distance to walk around arc UT, you calculate the diameter (distance around the circle) and you divide by 6 since UT is 1/6 of the circle.

the diameter of a circle can be calculated by 2*radius

the radius in the given (from S to T) is 10

2 * 10 = 20/6 = 10/3

10/3 is the distance to walk around UT

2. to find the area of one of the six sectors, you find the area of the whole circle and divide by 6 since you are only finding the area of ONE of the six sectors.

the area of a circle formula is A = πr^2

A = π10^2

A = π100

A= 314

divide by 6 to find the area of one sector

314 / 6 = 157 / 3

the area of one sector is 157/3

3. since you know the radius and the distance of one sector's curve, you can add all of these lengths by addition.

U to S = 10 (radius)

S to V = 10 (radius)

V to W = 10/3 (1/6 of the diameter)

W to X = 10/3 (1/6 of the diameter)

X to U = 20 (radius times 2 since you are going from one edge of the circle to the other)

40 + 20/3 is the distance to walk

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Me podrían ayudar y explicarme el proceso please
kakasveta [241]

Answer: Encontrarás las respuestas debajo de cada explicación. Espero que consideres darme brainliest y 5 estrellas, y más importante, que hayas entendido.

Step-by-step explanation:

Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

1 - 20kg

ahora queremos saber cuantas cajas (x) equivalen a 7653kg

x - 7653kg

Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

Pongamos la cantidad de cajas en la izquierda y el peso en la derecha

\frac{1}{x} =\frac{20kg}{7653kg}

Procedemos a multiplicar en cruz. Solo podemos multiplicar si tenemos ambos valores. En este caso, los valores en cruz que tenemos son 1 y 7653kg porque en la otra cruz (20 y x) tenemos nuestra incognita. Y, por ultimo, dividimos entre el numero cuya cruz es con la incognita (20kg)

Esto nos deja la expresión así;

x=\frac{1*7653kg}{20kg}

x=382.65

Como una caja no puede ser un numero decimal, redondeamos.

x=383

Por lo tanto, se necesitan aproximadamente 383 cajas para que su peso equivalga a 7653 kg.

-------------------------------------------------------------------------------------------------------

La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

\frac{1}{x}=\frac{20kg}{9500kg}

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

x=\frac{1*9500kg}{20kg}

x=475

Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

--------------------------------------------------------------------------------------------------------

Por último, la pregunta dice, ¿Cuántos kilogramos hay en 873 cajas?

Ya sabemos que una caja pesa 20kg ( 1 - 20kg ) y ahora buscamos cuantos kg hay en 873 cajas; es decir, (873 - x)

Nos quedaría así;

\frac{1}{873}=\frac{20kg}{x}

Ahora, nuestra cruz es 873 y 20kg, y el divisor es 1.

x=\frac{873*20kg}{1}

x=17460kg

Este sería el peso de 873 cajas.

5 0
3 years ago
Which of the graph of f(x)=x-1/x^2-x-6
Alik [6]

Answer:

a on edge

Step-by-step explanation:

3 0
3 years ago
A. A fair 6-face die will be rolled some number of times, and you win if it shows an ace (one spot) 20% or more of the time. Oth
butalik [34]

Answer: The complete question is found in the attachment

Step-by-step explanation:

Law of large numbers: The probability of occurrence of an event becomes closer to the theoretical probability as the number of trials increases

P(an ace) = 1/6

= 0.1667

= 16.67%

a) In 600 rolls, the value will be close to 16.67. compared to 60 rolls

Greater than 20% interval doesn't include 16.67%. So, for more than 20% ace, 60 rolls is better.

b) More than 15% interval includes 16.67. So, it is better to roll 600 times

c) The interval between 15% and 20% include 16.67% and hence, 600 rolls is better

d) Larger number of trials is better to get exactly 16

So, 600 rolls is better

4 0
4 years ago
GEOMETRY PLEASE HELP! THANK TOU SO MUCH :)
Anna71 [15]

Answer:

11. X=76

Step-by-step explanation:

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3 years ago
Edward has 18 apples and 16 oranges to share. He has 26 friends in his class. He wants to give each friend one fruit. How many f
jasenka [17]

Answer:

he' ll have 8 fruits left

Step-by-step explanation:

18 + 16  =  34 ,  34-26 = 8

5 0
2 years ago
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