11. 2x+3x+1=21
5x+1 =21
5x=20
x=4
TU= 2(4) which is 8
UB= 3(4)+1 which is 13
12. 4x-1 +2x-1=5x
6x-2=5x
-2=-1x
2=x
X=2
TU= 7
UB= 3
TB=10
Problem 13:
2x-8=x+17
2x=x+25
x=25
AB =42
BC=42
AC=84
Problem 14:
3x-31
-x+6
=
2x-37 for BC part now we solve for x
x+6=2x-37
6=x-37
43=x
So :
X=43
AB=49
AC=98
BC=49
<span>|7x-7|+3 = 4x+1 ⇒⇒⇒ add (-3) to both sides
</span>
<span>∴ |7x-7| = 4x - 2
</span>
According to the absolute rule
∴ 7x - 7 = 4x - 2 OR -(7x - 7) = 4x - 2
7x - 4x = 7 - 2 l 7x - 7 = -4x + 2
3x = 5 l 7x + 4x = 2 + 7
x = 5/3 l 11 x = 9 ⇒⇒⇒ x = 9/11
∴ x = 5/3 and 9/11
So, the correct answer is option <span>B. 5/3 and 9/11</span>
Answer:
The given theorem proves that the door is not a rectangle right now since, the door came out of shape, it can be proved by the Pythagorean theorem. If the length is set to a certain shape, and the width is set to a certain shape, and drawn to diagonals. If solved by the Pythagorean Theorem, if the length of two diagonals are similar then and only then the door would be a rectangle.
Hope this helps!
