|RZ|=0.5|SW| therefore 2|RZ|=|SW|.
5x - 20 = 2 · 30
5x - 20 = 60 |add 20 to both sides
5x = 80 |divide both sides by 5
x = 16
<u>Answer:</u>
- 6. 6.75
- 7. 27
- 8. 92/17
- 9. 49
<u>Step-by-step explanation:</u>
<u>- Question 6 -</u>
- 9/16 = x/12
- => 16x = 12 x 9
- => 16x = 108
- => x = 6.75
Hence, <u>the value of x in this proportion is 6.75.</u>
<h3>_______________________________</h3>
<u>- Question 7 -</u>
- -3 + x/18 = 12/9
- => -3/18 + x/18 = 4/3
- => x/18 = 4/3 + 1/6
- => x/18 = 8/6 + 1/6
- => x/18 = 9/6
- => x = 9/6 x 18
- => x = 27
Hence, <u>the value of x is 27</u>
<h3>_______________________________</h3>
<u>- Question 8 -</u>
17/15 = 10/2x - 2
=> 17(2x - 2) = 150
=> 34x - 34 = 150
=> 34x = 184
=> x = 184/34
=> x = 92/17
Hence, <u>the value of x is 92/17</u>
<h3>_______________________________</h3>
<u>- Question 9 -</u>
- x - 16/x + 6 = 3/5
- => 5(x - 16) = 3(x + 6)
- => 5x - 80 = 3x + 18
- => 2x = 98
- => x = 49
Hence, <u>the value of x is 49.</u>
<h3>_______________________________</h3>
Hoped this helped.
Any number ends with 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9
Given any number. The square of this number is the last digit of square of the original numbers units digit.
For example
23*23 ends with 9 (3*3=9)
149*149 ends with 1 (9*9=81)
2564*2564 ends with 6 (4*4=16)
and so on
so all the possible unit digits of a square number are {0, 1, 4, 5, 6, 9}
because:
0*0= 0 ; 1*1=1; 2*2=4; 3*3=9; 4*4=16; 5*5=25, 6*6=36; 7*7=49; 8*8=64, 9*9=81
Thus, the probability that the square of a number selected from any set of numbers being 7, is 0.
Answer: 0
Answer:
The box to the left will have the equation p(x) = 5x² and the box to the right will have the equation n(x) = 
Step-by-step explanation:
The coefficient of the x² decides how wide or narrow a quadratic graph is. If the coefficient is a fraction of 1, the smaller the fraction the wider the graph gets. If the coefficient is a number bigger than 1, the bigger the number, the narrower the graph gets.
To find the superficial area of a prism you have to do base perimeter * height
So find the perimeter of the right triangle: 9+8+5 = 22 yd
Then find the superficial area 22*12 = 264 yd^2
