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GrogVix [38]
3 years ago
6

A car is going 10 miles per hour when the driver hits the breaks. The car travels 3 feet after the brakes are applied. A little

while later, the same car is going 20 miles per hour. This time, when the driver hits the brakes about how far does the car travel after the brakes are applied
Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer:

6

Step-by-step explanation:

10/3=20/x

20/10=2

x/3=3*2

x=6

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Work out the circumference of this circle.
Arada [10]

Answer: 52.7856cm

Step-by-step explanation:

Circumference of a circle = 2πr

Note that radius = Diameter / 2 = 16.8/2 = 8.4cm

Circumference = 2πr

= 2 × 3.142 × 8.4

= 52.7856cm

Therefore, the circumference of the circle is 52.7856cm

6 0
3 years ago
What is the Slope= 7, (3,9)
lisov135 [29]
Where is the question? I have no idea what I need to do to help u?
5 0
3 years ago
Can someone please help me??
Nesterboy [21]

Answer:

Answers are below

Step-by-step explanation:

x     y

0    $25,001.00

1     $25,000.95

2    $25,000.90

3    $25,000.86

I graphed the function on the graph below and found the values of y for each value of x.

*My graph showed that the initial value of the printer was $25,001.00, instead of $25,000.00*

7 0
2 years ago
What is the value of the variable in the equation, 83=y-99 *
soldier1979 [14.2K]

Answer: y= 182

Step-by-step explanation:

flip equation (y-99=83) and add 99 to both sides. the two 99's will cancel and 83+99 is 182 whihc is the answer.

5 0
3 years ago
Read 2 more answers
Evaluate the function at the indicated values if possible. If an indicated value is not in the​ domain, say so.
goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

f(x)=\frac{x+7}{x^2-9} is the given function.

We are asked to find:

f(-7)

f(2)

f(3).

f(-7) means to replace x in the expression called f with -7:

Evaluate \frac{x+7}{x^2-9} at x=-7

\frac{(-7)+7}{(-7)^2-9}

\frac{0}{49-9}

\frac{0}{40}

0

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate \frac{x+7}{x^2-9} at x=2

\frac{2+7}{2^2-9}

\frac{9}{4-9}

\frac{9}{-5}

\frac{-9}{5}

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate \frac{x+7}{x^2-9} at x=3

\frac{3+7}{3^2-9}

\frac{10}{9-9}

\frac{10}{0}

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0
3 years ago
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