Money to be spent per day <$100
To rent a car:
Minimum amount per day= $45
Amount per mile= $0.25

Hence amount spent depends on distance travelled.
If distance travelled= x; fee for travel= 0.25x

Hence finally we need the fare to be less than $100
And fare is $45+0.25x

So the final inequality is 0.25x+45<100.

Hope it helps.

8 0

3 years ago

What is greater -5.06 or 5.6

sukhopar [10]

$-5.06 < 5.6 \\\\ 5.6 -is \ a \ positive \ number \ so \ is \ always \ bigger \ than \ a \ negative \ one$

4 0

3 years ago

Read 2 more answers

What is the value of a?

zubka84 [21]

Not enough information

5 0

3 years ago

Read 2 more answers

For the month of March in a certain city, 57% of the days are cloudy. Also in the month of March in the same city, 55% of the da

oksian1 [2.3K]

Answer: 0.9649

Step-by-step explanation:

Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.

Given : For the month of March in a certain city, the probability that days are cloudy : $P(A)=0.57$

Also in the month of March in the same city,, the probability that the days are cloudy and rainy : $P(A\cap B)=0.55$

Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}$

$\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}$

Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649

4 0

3 years ago