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2 years ago

Élizabeth a 20 ans de moins que son père. Si son père est trois fois plus âgé qu’elle, détermine l’âge de chacun.

Mathematics

1 answer:

eduard2 years ago

4 0

Elizabeth is 20 years younger than her father. If her father is three times her age, determine the age of each.

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6 pounds of potatoes cost $11.34. What is the unit price?

AveGali [126]

Your answer would be $1.89

You take 11.34 and divide it by 6. After that you’ll be 1.89 as your unit price.

1.89 is how much for 1 pound

8 0

2 years ago

2/3 is what percent of 1/4

mario62 [17]

2/3 is 266.66% of 2/4.

(2/3)(1/4)=(2/3)(4/1)=8/3=2 2/3=2.6666=266.66

hope this helps!!

4 0

2 years ago

Find two integers whose sum is 3 and product is -108.

AleksandrR [38]

Answer:

12 and -9

Step-by-step explanation:

12 x -9 = -108

12 + -9 = 3

7 0

2 years ago

What is the sum of a 7-term geometric series if the first term is -6, the last term is -24,576, and the common ratio is 4?

Zanzabum

<h3><u>Answer:</u></h3>

Hence, the sum of a 7-term geometric series is:

-32766.

<h3><u>Step-by-step explanation:</u></h3>

We have to find the sum of a 7-term geometric series (i.e. n=7) if the first term(a) is -6, the last term is -24,576, and the common ratio(r) is 4.

We know that the sum of the 7-term geometric series is given as:

$S_n=a\times (\dfrac{r^n-1}{r-1})$

On putting the value of a,n and r in the given formula we have:

$S_7=(-6)\times (\dfrac{4^7-1}{4-1})\\\\\\S_7=-32766$

Hence, the sum of a 7-term geometric series is:

-32766.

3 0

3 years ago

Read 2 more answers

Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

Comparing equations (A) and (B), we have

$5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.$

Thus,

$AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.$

8 0

3 years ago