Answer:
- (x -1)(x +6)
- (x -5)(x +3)
- (x -4)(x -3)
Step-by-step explanation:
In each case, you're looking for divisors of the constant that have a sum equal to the x-coefficient. Those divisors are the constants in the binomial factors.
1) -6 = -1·6 = -2·3 . . . . . (-1)+(6) = 5, so these are the constants of interest.
x^2 +5x -6 = (x -1)(x +6)
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2) -15 = -1·15 = -3·5 = -5·3 . . . . . (-5)+(3) = -2, so these are the constants of interest
x^2 -2x -15 = (x -5)(x +3)
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3) 12 = -1·-12 = -2·-6 = -3·-4 . . . . . (-3) +(-4) = -7, so these are the constants of interest
x^2 -7x +12 = (x -3)(x -4)
