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PtichkaEL [24]
3 years ago
13

If anyone understands can you please help me✨‍♀️

Mathematics
1 answer:
sergiy2304 [10]3 years ago
4 0
180 mins to walk 12 miles :)
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Needing some help for my online class thanks
pav-90 [236]

Answer:

y=1/2x+2

Step-by-step explanation:

Know that: y=mx+b

Starting for (0,0) count how many times you go up to the marked line (which is 2)

y=1/2x+2

The [+] 2 is where you would start off at on the graph, with 1/2 being the slope go up one and over two.

7 0
2 years ago
HALT! DON'T MOVE A MUSCLE! CLICK HERE AND HELP ME OUT?! BRAINLIEST ANSWER INCLUDED! it costs $10 to place an advertisement in th
SashulF [63]

The ordered pairs are probably (0,10) and then (-1,5).

7 0
3 years ago
HURRY PLEASE I NEED IT ASAP 15 POINTSS!!!!
expeople1 [14]
D shows equivalent expressions
3 0
2 years ago
Read 2 more answers
Simplify 14 to the 15th power over 14 to the 5th power
stiks02 [169]

Answer:

d) 14^10.

Step-by-step explanation:

14^15 / 14^5

= 14^(15-5(

= 14^10.

6 0
3 years ago
Mr. Jones purchased two sodas.
kondaur [170]

Answer:

  the prices were $0.05 and $1.05

Step-by-step explanation:

Let 'a' and 'b' represent the costs of the two sodas. The given relations are ...

  a + b = 1.10 . . . . the total cost of the sodas was $1.10

  a - b = 1.00 . . . . one soda costs $1.00 more than the other one

__

Adding these two equations, we get ...

  2a = 2.10

  a = 1.05 . . . . . divide by 2

  1.05 -b = 1.00 . . . . . substitute for a in the second equation

  1.05 -1.00 = b = 0.05 . . . add b-1 to both sides

The prices of the two sodas were $0.05 and $1.05.

_____

<em>Additional comment</em>

This is a "sum and difference" problem, in which you are given the sum and the difference of two values. As we have seen here, <em>the larger value is half the sum of the sum and difference</em>: a = (1+1.10)/2 = 1.05. If we were to subtract one equation from the other, we would find <em>the smaller value is half the difference of the sum and difference</em>: b = (1.05 -1.00)/2 = 0.05.

This result is the general solution to sum and difference problems.

5 0
2 years ago
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