Find the equation of the line that passes through (1,3) and is perpendicular to
2 answers:
Answer:
perpendicular lines have the same gradient
y=2x+3
The gradient of the two lines is 2
Gradient=change in y/change in x
=y2-y1/x2-x1
Let (x,y) also lie on the line
2= y-3/x-1
2(x-1) =y-3
2x-2=y-3
2x-y=-3+2
2x-y= -1
2x+1 =y
y=2x+1
Step-by-step explanation:
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Answer:
y=-1/2x+7/2
Step-by-step explanation:
Gradient is negative reciprocal so -1/2x
3=-1/2x + 7/2
y=-1/2x+7/2
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