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lapo4ka [179]
3 years ago
13

The table below shows the cost of sending packages of various weights.

Mathematics
2 answers:
jonny [76]3 years ago
8 0

the answer is 2.24!

Step-by-step explanation: hope this helped

chubhunter [2.5K]3 years ago
7 0
The correct answer would be $1.28
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What is the x-component of the electric field at (x, y) = (0 m, 4 m)??
Elza [17]
(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.

What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.

What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.

What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.
8 0
3 years ago
general admission tickets to the fair cost $3 per person ride passes cost an additional $5 per person parking tickets cost 7 dol
chubhunter [2.5K]

Answer:

5 people attended the fair.

Step-by-step explanation:

The parking tickets were 7 for the whole fam. You can subtract that off to get you $40. Each person cost $3+$5=$8. 40/8=5.

Hope this helps!

8 0
3 years ago
Dee lives in Michigan, which has a state income tax rate of 4.35%. She earns $2,200 per week.
babymother [125]

answer is $4,976.40

example  $2,200 x 0.0435 x 52 = $4, 976.40

5 0
2 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
DJ wants to install a zipline between two trees. The zipline will be strung
jolli1 [7]

Answer:

104 ft total

Step-by-step explanation:

52 times 2 equals 104

8 0
3 years ago
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