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Tresset [83]
3 years ago
10

Find the x- and y-intercepts of the graph of x+y=17x+y=17d

Mathematics
1 answer:
butalik [34]3 years ago
5 0

Answer:

fbdjenfg,scsv

Step-by-step explanation:

jgfnhgfbfu generally

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Write an equation for the nth term of the arithmetic sequence −15, −33, −51, −69, .... An equation for the nth term of the
stira [4]

Given:

The arithmetic sequence is −15, −33, −51, −69.

To find:

The nth term of the arithmetic sequence.

Solution:

We have,

−15, −33, −51, −69

Here,

First term: a = -15

Common difference is

d = -33-(-15)

d = -33+15

d = -18

Now, nth term  of an arithmetic sequence is

a_n=a+(n-1)d

Substitute a=-15 and d=-18.

a_n=-15+(n-1)(-18)

a_n=-15-18n+18

a_n=-18n+3

Therefore, the nth term of the given arithmetic sequence is a_n=-18n+3.

4 0
3 years ago
In ΔIJK, j = 540 inches, ∠I=54° and ∠J=69°. Find the area of ΔIJK, to the nearest square inch.
xenn [34]

Answer:

105963

Step-by-step explanation: delta math

3 0
3 years ago
While training for a marathon, Jeff wants to increase the number of miles he runs each day. On the first day of training, Jeff r
user100 [1]

Answer:

The series is 5 , 6 , 7 , 8 , 9 , 10 , 11

Step-by-step explanation:

* Lets revise the arithmetic series

- In the arithmetic series there is a constant difference between

 each two consecutive numbers

- Ex:

# 2  ,  5  ,  8  ,  11  ,  ……………………….  (constant difference is 3)

# 5  ,  10  ,  15  ,  20  ,  …………………………  (constant difference is 5)

# 12  ,  10  ,  8  ,  6  ,  ……………………………  (constant difference is -2)

* General term (nth term) of an Arithmetic series:

- If the first term is a and the common diffidence is d, then

 U1 = a  ,  U2  = a + d  ,  U3  = a + 2d  ,  U4 = a + 3d  ,  U5 = a + 4d

- So the nth term is Un = a + (n – 1)d, where n is the position of the

 number in the series

* Lets solve the problem

- Jeff wants to increase the number of miles he runs each day

∴ He will add the initial value by constant number each day

- He plans on increasing the number of miles he runs a day by 1

∴ The constant value is 1 mile

-  On the first day of training, Jeff runs 5 miles

∴ The first value is 5 miles

∴ The series is arithmetic

∵ a = 5 , d = 1

- He do that for the remainder of the week

∵ The week has 7 days

∴ The series has 7 terms

∵ The rule of the series is Un = a + (n - 1)d

∵ a = 5 and d = 1

∴ Un = 5 + (n - 1)(1)

∴ Un = 5 + n - 1

∴ Un = 4 + n ⇒ n is the position of the number

- Substitute n from 1 to 7 to find the series

∴ The series is 5 , 6 , 7 , 8 , 9 , 10 , 11

6 0
4 years ago
Evaluate the integral x^3 (x 4 −8)^44 dx by making the substitution u = x^4 - 8
Eduardwww [97]

Answer:

(x^4-8)^45 /180 +c

Step-by-step explanation:

If u=x^4-8, then du=(4x^3-0)dx or du=4x^3 dx by power and constant rule.

If du=4x^3 dx, then du/4=x^3 dx. I just divided both sides by 4.

Now we are ready to make substitutions into our integral.

Int(x^3 (x^4-8)^44 dx)

Int(((x^4-8)^44 x^3 dx)

Int(u^44 du/4)

1/4 Int(u^44 dul

1/4 × (u^45 / 45 )+c

Put back in terms of x:

1/4 × (x^4-8)^45/45 +c

We could multiply those fractions

(x^4-8)^45 /180 +c

5 0
3 years ago
What's one fifth of 45
pishuonlain [190]
1 /5 = 0 . 2 
45 * . 2 = 9
Hope this helped :)
3 0
4 years ago
Read 2 more answers
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