Answer:
a)$12180.53
b)A=P(1-r)^n
Step-by-step explanation:
The formula for depreciation to use is this case is;
A=P(1-r)^n
where
A=value of boat after 5 years
P=current value of boat = $45000
r=rate of depreciation= 23% =0.23
n=time span after the boat was boat= 5 yrs
Applying the formula
A=$45000(1-0.23)^5
A=$45000(0.77)^5
A=$12180.53
Answer:
2177.5
Step-by-step explanation:
5x435.5=2177.5
Answer:
3
Step-by-step explanation:
When you multiply .3 by 10, you will end up with the answer of three. There are three more ounces in the jar.
Answer:
See Explanation
Step-by-step explanation:
Required
Proportion problems
An example is:
y is directly proportional to x such that: y=4 when x = 2;
Derive the equation
For direct proportions, we have:
![y\ \alpha\ x](https://tex.z-dn.net/?f=y%5C%20%5Calpha%5C%20x)
This gives:
![y = kx](https://tex.z-dn.net/?f=y%20%3D%20kx)
Make k the subject
![k = y/x](https://tex.z-dn.net/?f=k%20%3D%20y%2Fx)
So:
![k = 4/2 =2](https://tex.z-dn.net/?f=k%20%3D%204%2F2%20%3D2)
So, the equation is:
![y = kx](https://tex.z-dn.net/?f=y%20%3D%20kx)
![y = 2x](https://tex.z-dn.net/?f=y%20%3D%202x)
Assume the above question is for inverse proportion
The variation will be:
![y\ \alpha\ \frac{1}{x}](https://tex.z-dn.net/?f=y%5C%20%5Calpha%5C%20%5Cfrac%7B1%7D%7Bx%7D)
This gives:
![y\ = \frac{k}{x}](https://tex.z-dn.net/?f=y%5C%20%3D%20%5Cfrac%7Bk%7D%7Bx%7D)
Make k the subject
![k =x*y](https://tex.z-dn.net/?f=k%20%3Dx%2Ay)
![k =2* 4 = 8](https://tex.z-dn.net/?f=k%20%3D2%2A%204%20%3D%208)
So, the equation is:
![y\ = \frac{k}{x}](https://tex.z-dn.net/?f=y%5C%20%3D%20%5Cfrac%7Bk%7D%7Bx%7D)
![y = \frac{8}{x}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B8%7D%7Bx%7D)