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GrogVix [38]
2 years ago
11

HELPPPP PLEASEEEE will give brainliest ​

Mathematics
1 answer:
ycow [4]2 years ago
8 0

Answer:

I think it's the 3rd or fourth one. I'm not positive tho

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Jonah is going to the store to buy candles. Small candles cost $2.50 and large candles cost $7.00. He needs to buy at least 20 c
artcher [175]

<em><u>The system of linear inequalities are:</u></em>

a + b \geq 20\\\\2.50a + 7b\leq 80

<em><u>Solution:</u></em>

Let "a" be the number of small candles bought

Let "b" be the number of large candles bought

<em><u>He needs to buy at least 20 candles</u></em>

Therefore, number of small candles and number of large candles bought must be at least 20

Thus, we frame a inequality as:

a + b \geq 20

"at least" means greater than or equal to

Here, we used "greater or equal to" symbol because, he can buy 20 candles or more than 20 candles also

From given,

Cost of 1 small candle = $ 2.50

Cost of 1 large candle = $ 7

<em><u>He can spend no more than 80 dollars</u></em>

Which means, he spend maximum 80 dollars or less than 80 dollars also

So we have to use "less than or equal to" symbol

<em><u>Thus, we frame a inequality as:</u></em>

Number of small candles bought x Cost of 1 small candle + number of large candles bought x Cost of 1 large candle \leq 80

a \times 2.50 + b \times 7 \leq 80\\\\2.50a + 7b\leq 80

<em><u>Thus the system of linear inequalities are:</u></em>

a + b \geq 20\\\\2.50a + 7b\leq 80

3 0
2 years ago
1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6)<br> 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)
vlada-n [284]

1.

(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

2.

(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10

3 0
2 years ago
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