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How do you solve 7(7a-9)>84
1 answer:
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The integers are 12, 14.
Solution:
Let the even consecutive integers be x and x + 2.
Lesser number = x and Greater number = x + 2
Lesser number = Half of greater number + 5
To add the numbers, denominators must be same. So multiply 5 by .
Multiply by 2 on both sides, we get
⇒ 2x = x + 12
Subtract x from both sides.
⇒ x = 12
Lesser number = 12
Greater number = 12 + 2 = 14
Hence the integers are 12, 14.