We can group the expression x³ + 4x² + 5x + 20 as (x³ + 4x²) + (5x + 20). We have factor out the common factors and have
(x³ + 4x²) + (5x + 20)
x²(x + 4) + 5(x + 4)
From this, we have x³ + 4x² + 5x + 20 = x²(x + 4) + 5(x + 4). And thus, the answer is <span>B.</span>
In a rational function, holes are located where f(x) is undefined(the denominator is 0), but the undefined points can be factored out. In f(x), when x is 4 or -3, f(x) is undefined. But, x+3 can be factored out, so it is a hole. The hole is located at (-3,-1/7)
Answer:
-20
Step-by-step explanation:
(r + b − g)(b + g)
we have fom statement:
r = 9
b = 5
g= −6
so we have:
(r + b − g)(b + g)= (9+5-(-6))*(5+(-6))
(r + b − g)(b + g)= (14+6)*(-1)
(r + b − g)(b + g)= -20
