Answer:
a) 19/15 b) 1/3
Step-by-step explanation:
in both the question I reduced the numbers with 5
The answer is -7 hope this helps!
Answer:
20/3 ounces of water is added.
Step-by-step explanation:
how many ounces of pure water should be added to 20 ounces of 40% solution of muriatic acid to obtain a 30% solution of muriatic acid?
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The acid is 40% of 20 ounces = 8 ounces.
0.4*20 = 8
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That same 8 ounces is to be 30%. The water will be the other 70%.
8/30 = x/100
30x = 800
x = 80/3, the total amount of the solution.
We started with 20, so 80/3 - 20 = 20/3
20/3 ounces of water is added.
What vectors? do you have more info?
Answer:
y = -49
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
-7 = y/7
<u>Step 2: Solve for </u><em><u>y</u></em>
- Multiply 7 on both sides: -49 = y
- Rewrite: y = -49
