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3 years ago

PLEASE HELP ME! A. 90° B. 125° C. 35° D. 55°

Mathematics

2 answers:

otez555 [7]3 years ago

8 0

Answer:

A que tu novio

Step-by-step explanation:

beks73 [17]3 years ago

5 0

Answer:

m=180-90-35

m=55°

...............

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Which of the following situations results in 2/3 ? Select three that apply

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Answer:

The first, second, and fourth questions.

Step-by-step explanation:

None of these result in an answer of 23, so I'm assuming that you meant 2/3.

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2 years ago

Figure ABCD is a parallelogram.

Eddi Din [679]

Answer:

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3 years ago

Read 2 more answers

A regular pentagon ABCDE is shown work out angle x

kow [346]

Answer:

108 degrees inside each corner

Step-by-step explanation:

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5 0

4 years ago

6 high school seniors choose from among 20 quotes for their yearbook. What is the probability that at least 2 of them choose the

shusha [124]

Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem, we have that:

There are 6 students, hence n = 6.

There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.

The probability of one quote being chosen at least two times is given by:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

P(X < 2) = P(X = 0) + P(X = 1).

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.05)^{0}.(0.95)^{6} = 0.7351$

$P(X = 1) = C_{6,1}.(0.05)^{1}.(0.95)^{5} = 0.2321$

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9672 = 0.0328$

0.0328 = 3.28% probability that at least 2 of them choose the same quote.

More can be learned about the binomial distribution at brainly.com/question/24863377

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2 years ago

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Tasya [4]

Answer: maybe 20 cm

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3 years ago