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VLD [36.1K]
3 years ago
7

I need help please.

Mathematics
1 answer:
JulijaS [17]3 years ago
3 0

Answer:

\frac{7\sqrt{5} }{8}

Step-by-step explanation:

Using the rules of radicals

\sqrt{\frac{a}{b} } = \frac{\sqrt{a} }{\sqrt{b} }

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Given

\sqrt{\frac{245}{64} } = \frac{\sqrt{245} }{\sqrt{64} }

Simplifying the radicals

\sqrt{245}

= \sqrt{5(7)(7)}

= \sqrt{49(5)}

= \sqrt{49} × \sqrt{5} = 7\sqrt{5}

and

\sqrt{64} = 8

The simplified radical is

\frac{7\sqrt{5} }{8}

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Graph a parabola whose x-intercepts are at x=-3 and x=5 and whose minimum value is y=-4
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Answer:

(See explanation for further details)

Step-by-step explanation:

The standard equation of the parabola is:

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The formula is now expanded into a the form of a second-order polynomial:

y + 4 = C\cdot x^{2} -2\cdot C\cdot k \cdot x +C\cdot k^{2}

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The general equation of the second-order polynomial is:

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The equations to be solved are presented herein:

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Now, the solution of the system is:

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C = \frac{1}{4}

k = 5 - \frac{2}{\sqrt{\frac{1}{4} }}

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The equation of the parabola is:

y = \frac{1}{4}\cdot (x-1)^{2} -4

Lastly, the graphic of the function is included as attachment.

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3 years ago
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